Answer:
i also need the is question help!!!
Explanation:
 
        
             
        
        
        
Answer:
It was called MANURE 
Explanation:
Its a type of fertilizer which plant are ploughed back into the soil.
GOOD LUCK 
 
        
             
        
        
        
Explanation:
there you go you can just look up atomic model for CD and click images
 
        
             
        
        
        
Answer:
D. (16.0 g + 16.0 g) × 100% / (32.1 g + 16.0 g + 16.0 g) = 49.9%
Explanation:
Step 1: Detemine the mass of O in SO₂
There are 2 atoms of O in 1 molecule of SO₂. Then,
m(O) = 2 × 16.0 g = 16.0 g + 16.0 g = 32.0 g
Step 2: Determine the mass of SO₂
m(SO₂) = 1 × mS + 2 × mO = 1 × 32.1 g + 2 × 16.0 g = 32.1 g + 16.0 g + 16.0 g = 64.1 g
Step 3: Detemine the mass percent of oxygen in SO₂
We will use the following expression.
m(O)/m(SO₂) × 100%
(16.0 g + 16.0 g) × 100% / (32.1 g + 16.0 g + 16.0 g) = 49.9%
 
        
             
        
        
        
Acids are corrosive, which means they 'eat away' at other materials.