All three series converge, so the answer is D.
The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.
Consider a geometric sequence with the first term a and common ratio |r| < 1. Then the n-th partial sum (the sum of the first n terms) of the sequence is
Multiply both sides by r :
Subtract the latter sum from the first, which eliminates all but the first and last terms:
Solve for :
Then as gets arbitrarily large, the term will converge to 0, leaving us with
So the given series converge to
(I) -243/(1 + 1/9) = -2187/10
(II) -1.1/(1 + 1/10) = -1
(III) 27/(1 + 1/3) = 18
Answer:
EZ
Step-by-step explanation:
Answer:
22.41
Step-by-step explanation:
take 4.98x4.5
Answer: B no
Step-by-step explanation:
Plot in the x and y coordinates into the equation to solve it.
The x coordinate is 4 and the y coordinate is 1
-4(4) +3(1)= 2
-16 + 3 = 2
-13 ≠2
-13 does not equal 2 so (4,1) is not a solution.
Answer:I believe the correct answer is D. As the formula to find the hypotenuse of a right triangle is c=√a^2+b^2
Step-by-step explanation: