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Lerok [7]
3 years ago
6

Identify the decimal with the largest value in the following set. 0.7, 0.67, 0.86, 0.0025.

Mathematics
2 answers:
11Alexandr11 [23.1K]3 years ago
6 0

Answer:

<h2>0.86</h2>

Step-by-step explanation:

This is surprisingly easy.

Just find the one with the biggest value in the biggest decimal place.

If you don't know what I'm talking about, you shouldn't be here.

dexar [7]3 years ago
3 0
I know this is already answered, but I kinda want to simplify this for you.

Decimals aren’t as scary as they seem. And when you’re looking for the largest one? You’re basically looking for the decimal that’s closest to the number one.

“What the heck does that mean?!” Well, let me explain...

A decimal number is basically part of one. For example, if we had .5, that number is half of one. .5+.5=1. Easy as that.

Now, if we were looking for the highest decimal we would need to see how for away from one all of them are...

1.0 1.00 1.00
-0.7 -0.67 -0.86
—— ——- -——
0.30 0. 33 0.14

.86 is the closest number to 1; it must be the greater decimal!

A really basic way to think about it is to try to see which decimal is closest to becoming a whole number. .86 is the closest because it is only .14 points away from becoming a 1; it’s almost there!

Hope this helped you understand a little better!!

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A dog shelter housed 24 puppies last month. This month, 39 puppies are at the shelter. What is the percent of change?
IgorLugansk [536]

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Step-by-step explanation:

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8 0
3 years ago
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Find the base in the following problem. 100 is 19% of what number?
Ket [755]
526.32

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4 0
4 years ago
Suppose that a box contains one fair coin (Heads and Tails are equally likely) and one coin with Heads on each side. Suppose fur
stealth61 [152]

Using conditional probability, it is found that there is a 0.1 = 10% probability that the chosen coin was the fair coin.

Conditional Probability

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem:

  • Event A: Three heads.
  • Event B: Fair coin.

The probability associated with 3 heads are:

  • 0.5^3 = 0.125 out of 0.5(fair coin).
  • 1 out of 0.5(biased).

Hence:

P(A) = 0.125 + 0.5 = 0.625

The probability of 3 heads and the fair coin is:

P(A \cap B) = 0.5(0.125) = 0.0625

Then, the conditional probability is:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0625}{0.625} = 0.1

0.1 = 10% probability that the chosen coin was the fair coin.

A similar problem is given at brainly.com/question/14398287

4 0
3 years ago
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