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Delvig [45]
3 years ago
14

What is 408 divided by 17 in long division?

Mathematics
2 answers:
Natalija [7]3 years ago
7 0
It's 24. here's the work >.<

stellarik [79]3 years ago
5 0
416 the six have a bar nation on the top:)
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Trigonometry Problem, only solve if you know how and can tell me how to solve it.
Crazy boy [7]

The distances from the point the plane leaves the ground are given by the

trigonometric relationships of right triangle and Pythagoras theorem.

  • A) The minimum distance to the base of the tower is approximately <u>874.57 ft</u>.
  • B) The minimum distance to the top of the tower is approximately <u>882.76 ft</u>.

Reasons:

A) The angle with which the airplane climbs, θ = 11°

Height of the tower which the airplane flies, T = 120 foot

The clearance between the tower and the airplane, C = 50 feet

Required:

The minimum distance between the point where the plane leaves the ground and the base of the tower, \displaystyle d_{min}}

Solution:

Height at which the plane flies over the tower, h = T + C

Therefore, h = 120 ft. + 50 ft. = 170 ft.

At the point the plane leaves the ground, we have;

  • \displaystyle tan(\theta) = \mathbf{\frac{h}{d_{min}}}

Which gives;

\displaystyle tan(11^{\circ}) = \frac{170 \, ft.}{d_{min}}

\displaystyle d_{min} = \mathbf{\frac{170 \, ft.}{tan(11^{\circ})}} \approx 874.57 ft.

  • The minimum distance between the point where the plane leaves the ground and the base of the tower, \displaystyle d_{min}} ≈ <u>874.57 ft</u>.

B) The minimum distance between the point where the plane leaves the ground and the tower, <em>R</em>, is given by Pythagoras's theorem as follows;

R² = \displaystyle \mathbf{d_{min}}}² + T²

Which gives;

R = √(*874.57 ft.)² + (120 ft.²)) ≈ 882.76 ft.

  • The distance from the point where the airplane leaves the ground to the tower, R ≈ <u>882.76 ft</u>.

Learn more about Pythagoras theorem here:

brainly.com/question/11256912

7 0
2 years ago
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