A person can only have two allele of a character, therefore, the genotype of a male parent can be IBIB or IBi and the genotype of female parent can be IAIA or IAi. Therefore during gamete formation, all allele will segregate and assort independently.

So all the possible combinations are possible that are IAIB, IAi, IBi or ii because all the allele can be present in the two parents in which one have A blood group and another have B blood group.

Therefore their children could have A, B, AB, or O blood group so the correct answer is e. all of the above.

7 0

4 years ago

A cell’s progression through the cell cycle requires the activity of several cyclin-dependent kinases. What are these cdks, how

notka56 [123]

Answer: 1. Cyclin-dependent kinases.

2. The activation process is in two steps: binding of cyclin to cdk and then phosphorylation of cdk cyclin.

3. They are activated when cdks sends signals to cell that is pass already into the next stage of the cell cycle.

4. They are inactivated by the combination of P21 and Thr-14/Tyr-15 phosphorylation after uv induced DNA damage.

5. Changes are seen in target protein level when cdks level rises.

6. The targets are protein that promotes cell divisions.

Explanation:

7 0

3 years ago

Analyze the result of a cross between two organisms that are both heterozygous for two different genes (AaBb) use a Punnett squa

krok68 [10]

(1) All the genotypes are as follows: AABB, AaBB, AABb, AaBb, aaBB, aaBb, AAbb, Aabb, aabb.

(2) Assuming that Aa is dominant and Bb is recessive, there will be 9 phenotypes with both A and B allele dominant (i.e. AaBb, AABb); there will be 3 phenotypes with just the A allele dominant (i.e. Aabb, AAbb); there will be 3 phenotypes with just the B allele dominant (i.e. aaBb, aaBB); and there will be 1 phenotype with both alleles recessive (i.e. aabb). The phenotypic ratio in this case is 9:3:3:1.

(3) The probability of producing an offspring with the aabb genotype is 1/16 or 6%.

4 0

4 years ago