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andreev551 [17]
3 years ago
7

The perimeter of a rectangle is 60 m and its length is twice its width. find the length of the rectangle

Mathematics
1 answer:
GREYUIT [131]3 years ago
4 0
Length = 2W

P= 2L + 2W
60 = 2(2W) + 2W
60= 4W +2W
60 = 6W
60/6W = 6W/6W
w = 10
Length = 2(10)
Length = 20

P= 2L + 2W
60= 2(20) + 2(10)
60= 40 +20
60 = 60
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<em>L = 2*h + 2*w + w    (eq2)    (an extra distance w beacuse of the division)</em>

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<em>Solving for w:</em>

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<em>We derive this and equal zero to find its maximum:</em>

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<em>h = 120 ft.  Replacing this into eq3:</em>

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<em>w = 80ft</em>

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