Answer:
40 g NaOH
Step-by-step explanation:x
To make 500 mL of a 2 mol·L⁻¹ solution, the technician must measure the correct mass of NaOH.
Step 1. Calculate the <em>moles of NaOH
</em>
c = n/V Multiply both sides by V
n = Vc
c = 2 mol·L⁻¹
V =0.5 L
n = 0.5 × 2
n = 1 mol NaOH
Step 2. Calculate the <em>mass of NaOH
</em>
The molar mass of NaOH is 40.00 g/mol.
m = 1 × 40.00/1
m = <em>40 g NaOH
</em>
The technician must measure <em>40 g of NaOH</em>.
Answer:
Hg2^2+(aq) + 2Cl^-(aq) —> Hg2Cl2(s)
Explanation:
The balanced equation for the reaction is given below:
2NaCl(aq) + Hg2(NO3)2(aq) —> 2NaNO3(aq) + Hg2Cl2(s)
Considering the states of each compound in the reaction, we can see that Hg2Cl2 is in solid form meaning it will precipitate out of the solution
In solution the following occurs:
NaCl —> Na+(aq) + Cl-(aq)
Hg2(NO3)2 —> Hg2^2+(aq) + 2NO3^-(aq)
Combining the two equation together, a balanced double displacement reaction occurs as shown below:
2Na+(aq) + 2Cl-(aq) + Hg2^2+(aq) + 2NO3^-(aq) —> 2Na+2NO3^-(aq) + Hg2^2+2Cl-(s)
From the above we can thus right the insoluble precipitate as
Hg2^2+(aq) + 2Cl^-(aq) —> Hg2Cl2(s)
The answer is a graduated cylinder
Because a heat is added to a substance
