Problem 57EDraw the Lewis structure for CO with an arrow representing the dipole moment. UseFigure 9.10 to estimate the percent ionic character of the CO bond. Step by step solutionStep 1 of 2Lewis structure of CO:Carbon has four valence electrons and oxygen has six valence electrons. If only one bond wereto be formed between carbon and oxygen atoms, carbon would have five electrons and oxygenwould have seven electrons.The single bond between these two atoms is not sufficient to lead to an octet on each atom . Tocomplete the octet of each atom in CO, we must employ a triple bond .A triple bond is formed bythe six electrons sharing between these two atoms and it is shown as follows.\nThe Lewis structure of CO with an arrow representing the dipole moment.The arrow towards anoxygen atom it represents is a highly electronegative atom.
Solution is homogeneous mixture which is made up of two or more substances.Solution is composed of solute and a solvent.Solute is the substance that dissolve while solvent is a liquid in which solvent dissolve. Solution involve a chemical change since new substance are formed and involve chemical reaction.
Answer:
4:Chlorophyll. 6. Photosynthesis 8. Glucose
Explanation:
If the concentration of cholesterol is 238mg/100ml:
238 mg ==> 100ml
2380 mg (or 2.38g) ==> 1000ml (1L)
So the concentration will be 2.38 g/L of cholesterol.
if the volume is 5.2 L, the total grams of cholesterol would be :
m = C . V = 2.38g/L * 5.2 L = 12.376 grams of cholesterol.
Answer:
a. C₄H₁₀/O₂ = 2:13 (example)
b. O₂/CO₂ = 13:8
c. O₂/H₂O = 13:10
d. C₄H₁₀/CO₂ = 2:8
e. C₄H₁₀/H₂O = 2:10
Explanation:
2C₄H₁₀ + 13O₂ ⟶ 8CO₂ + 10H₂O
The molar ratios are the same as the coefficients in front of the formulas.
