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erastovalidia [21]
4 years ago
12

Unknown element has two isotopes. Isotope A has a mass of 34 amu and abundance of 52%, isotope B has a mass of 33 amu and abunda

nce of 48%. Find average atomic mass of this element and express your
Chemistry
1 answer:
ZanzabumX [31]4 years ago
4 0

Answer:

x = 33.52 amu

Explanation:

It is given that,

Isotope A has a mass of 34 amu and an abundance of 52%, isotope B has a mass of 33 amu and an abundance of 48%.

Let x is the average atomic mass of this element. It can be calculated as follows :

x=52\%\ \text{of}\ 34+48\%\ \text{of}\ 33\\\\x=\dfrac{52}{100}\times 34+\dfrac{48}{100}\times 33\\\\x=0.52\times 34+0.48\times 33\\\\x=33.52\ \text{amu}

So, the average atomic mass of this element is 33.52 amu.

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If a weak acid is 25 deprotonated at ph 4 what would the pka be
elena-s [515]

4.48

pH=pKa+log([A-/HA])

25% deprotonated tells us that A- is .25 and that the rest (75% is protonated) thats .75.

4 = pKa + log \frac{.25}{.75}

4 - log \frac{.25}{.75}  = pKa

4.48=pKa

6 0
3 years ago
What quantity of potassium phosphate, in grams, is required to prepare 500.0 ml of solution where you the concentration of potas
Readme [11.4K]

Answer: 3.54

Explanation:

You're forgetting to divide by 3 for the 3 moles of potassium that are in potassium phosphate.

Potassium Phosphate= K3PO4

3 0
3 years ago
What’s the equation to solid calcium oxide reacts with hydrochloric acid to form a solution of calcium chloride and water as it’
meriva

Answer: CaO + 2HCl —> CaCl2 + H2O

Explanation:

3 0
4 years ago
What coefficient is needed to balance the reaction
tensa zangetsu [6.8K]

Answer:

OD. 2HCl

Explanation:

A balanced equation needs the equal # of each element on BOTH sides.

By putting a 2 in front of HCl you now have 2 hydrogens on both sides and 2 chlorines. The Ca and CO3 are already balanced.

5 0
2 years ago
A rigid container of O has a pressure of 340 kPa at a temperature of 713 K. What is the pressure at 273 K?
tia_tia [17]

Answer:

P₂ = 130.18 kPa

Explanation:

In this case, we need to apply the Gay-Lussack's law assuming that the volume of the container remains constant. If that's the case, then:

P₁/T₁ = P₂/T₂   (1)

From here, we can solve for the Pressure at 273 K:

P₂ = P₁ * T₂ / T₁   (2)

Now, all we need to do is replace the given data and solve for P₂:

P₂ = 340 * 273 / 713

<h2>P₂ = 130.18 kPa</h2>

Hope this helps

4 0
3 years ago
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