Here is the complete question.
Glycerol (C3H8O3), also called glycerine, is widely used in the food and pharmaceutical industries. Glycerol is polar and dissolves readily in water and polar organic solvents like ethanol. Calculate the mole fraction of the solvent in a solution that contains 1.61 g glycerol dissolved in 22.60 mL ethanol (CH3CH2OH; density = 0.7893 g/mol). Round to four significant digits
Answer:
0.9567 mol
Explanation:
Given that:
mass of glycerol = 1.61 g
molar mass of glycerol = 92.1 g/mol
no of mole = 
∴ number of moles of glycerol (
) = 
= 0.0175 mol
Volume of ethanol = 22.60 mL
Density of ethanol = 0.7893 g/mL
Since Density = 
∴ mass of ethanol = density of ethanol × volume of ethanol
mass of ethanol = 0.7893 g/mL × 22.60 mL
mass of ethanol = 17.838 g
Number of moles of ethanol 
= 
= 0.387 mole
∴ the mole fraction of the solvent can be determined as:
= 0.95673671199
≅ 0.9567 mol
∴ The mole fraction of the solvent in a solution that contains 1.61 g glycerol dissolved in 22.60 mL ethanol is = 0.9567 mol
Answer:
The answer to your question is Aluminum
Explanation:
Number of clues
1.- If this element has 3 rings in its Bohr model, we are looking for and element located in the third period of the periodic table.
For example Sodium, Magnesium, Aluminum, Silicate, Phosphorus, Sulfur, Chlorine and, Argon.
2.- It makes three bonds to become stable, then we are looking for and element located in the third group like
Boron, Aluminum, Gallium, Indium, etc
Conclusion
The element that has both characteristics is Aluminum
It would be 1A bc then the +1 charge will cancel out chlorine’s -1 charge
C3H8+3O2--->3CO2+8H
Therefore for every 1:3 there are 3 Carbon dioxides that form. That means find the limiting reactant from the two reactants.
5.5g(1mole C3H8/44.03g of C3H8)=0.1249 moled of C3H8 and if for every one C3H8 we can form three CO2. We can assume 0.3747 miles of CO2 will be produced.
15g of O2(1 mole O2/32g of O2)=0.4685moles O2 and if for every three O2 we can produce three CO2 we may assume a 1:1 ratio.
This means C3H8 will be your limiting reactant. Therefore 0.3747 moles of CO2 will be produced.
0.3747 moles of CO2(48.01 g of CO2/1 mole of CO2)= 17.99 grams of CO2
Rubber it's not a conductor
