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Luba_88 [7]
3 years ago
10

Absolute value equations 10 6v + 3 = 30

Mathematics
1 answer:
konstantin123 [22]3 years ago
7 0
Your answers would be 30
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20 points, please help
Damm [24]

Answer:

The answer to your question is:    83 + 6\sqrt{35}

Step-by-step explanation:

This is a square of a binomial.

                                  (2\sqrt{5} + 3\sqrt{7} )^{2}

1.- Square of the first term

                               ( 2\sqrt{5} )^{2} = 4(5) = 20

2.- Twice the product of the two terms

               (2)(2\sqrt{5} )(3\sqrt{7} ) = 6\sqrt{35}

3.- Square of the second term

                              (3\sqrt{7)})^{2} = 9(7) = 63

4.- Write the solution

                           20 + 6\sqrt{35} + 63

                            83 + 6\sqrt{35}

7 0
4 years ago
For which set of data are the median and mode the same number?
dlinn [17]
1 hghhhhhhgghhghhhhhhhhhhhh
5 0
4 years ago
Paolo was asked to find the original dimension of an enlarged pentagon. His solution is shown next to the pentagons.
NISA [10]
The correct answer is the second choice.

Paolo made an error when he cross multiplied the proportion. He should have multiplied the 3 and the 8 and also the 12 and the x.

The second line should be:

12x = 24
6 0
4 years ago
Read 2 more answers
twice a number plus another number is 310. The difference between the two numbers is 55. What are the two numbers
Masteriza [31]
T us assume the two numbers to be "x" and "y".
Then
2x + y = 310
And
x - y = 55
Let us take the second equation and find the value of x in relation to y.
x - y = 55
x = y + 55
Now let us put the value of x in the first equation, we get
2x + y = 310
2(y + 55) + y = 310
2y + 110 + y = 310
3y = 310 - 110
3y = 200
y = 200/3
   = 66 2/3
Now putting the value of y in the second equation, we get
x - y = 55
x - (200/3) = 55
3x - 200 = 55 * 3
3x = 165 + 200
x = 365/3
   = 121 2/3
So the value of x is 121 2/3 and the value of y is 66 2/3

3 0
3 years ago
Read 2 more answers
I NEED AN ANSWER QUICK PLSSSSS
Roman55 [17]
It would be 100% death rates! hope this helps
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3 years ago
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