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Vikki [24]
3 years ago
8

0.3434343434 What is this as a fraction

Mathematics
1 answer:
nlexa [21]3 years ago
4 0

Answer:

34/99

Step-by-step explanation:

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Two straight lines VZ and YW intersect at X
Alexeev081 [22]

Answer:

∠WVX = 35°

Step-by-step explanation:

Look at the rough draw.

As you can see,

VW ║ YZ

So ∠XWV is congruent to ∠XYZ through alternate interior angle.

We can solve ∠WVX by considering the two other angles, 88° and 57°.

Total angle of a triangle is 180°.

So,

? + 88 + 57 = 180

? + 145 = 180

? = 180 - 145

? = 35°

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3 years ago
Assume that y varies directly with x. If y=9 when x=−3, find x when y=6.
Dafna1 [17]

Answer:-2

Step-by-step explanation:

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The pythogarean theorem,

Step-by-step explanation:

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Find the domain of the function y = 3 tan(23x)
solmaris [256]

Answer:

\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

In other words, the x in f(x) = 3\, \tan(23\, x) could be any real number as long as x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) for all integer k (including negative integers.)

Step-by-step explanation:

The tangent function y = \tan(x) has a real value for real inputs x as long as the input x \ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

Hence, the domain of the original tangent function is \mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

On the other hand, in the function f(x) = 3\, \tan(23\, x), the input to the tangent function is replaced with (23\, x).

The transformed tangent function \tan(23\, x) would have a real value as long as its input (23\, x) ensures that 23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

In other words, \tan(23\, x) would have a real value as long as x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right).

Accordingly, the domain of f(x) = 3\, \tan(23\, x) would be \mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

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iris [78.8K]

Answer:

Step-by-step explanation:The absoulte inequalities will have all real solutions asa solution so A, B, AND C  all apply.

The relations on the domain of the equation are,  C, AND A.

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3 years ago
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