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Sphinxa [80]
3 years ago
14

Would u have to add Fe or can someone walk me thru this

Physics
1 answer:
svetoff [14.1K]3 years ago
8 0
Chemical equations can be written down in 3 steps:

As example I’ll using the rusting of iron (as given)

1) Write down the products that react on the left side of the arrow.

2) Write the products after the reaction on the right side of the arrow. If there are one or more of a different atom that isn’t on the other side of the equation, the reaction is missing something on either sides.

Fe -> Fe2O3

But as you can see there are no O on the left side. The right formula is:

Fe + O2 -> Fe2O3

Review to make sure you wrote down everything.

3) Count all the atoms of each elements on each side. Balance out the amount of atoms on both sides by adding coefficients to your compounds

Take note that you need to multiply all the elements in the compound times the number

Fe + O2 -> Fe2O3

We need at least 2 iron atoms to balance out on the iron.

2Fe + O2 -> Fe2O3

Now we see that we have 2 O atoms on the left and 3 on the right. The smallest number that is divisable by both 2 and 3 is 6. Add coefficients in front of O2 and Fe2O3.

2Fe + 3O2 -> 2Fe2O3

Now we see that on the right there are 4 iron atoms. Balance out by multiplying iron on the left by 2.

4Fe + 3O2 -> 2Fe2O3

This is the final equation.
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Why does a rolling sphere slows down?​
Iteru [2.4K]
There’s frictional force acting on the sphere, which causes it to gradually slow down, and eventually come to a stop.
4 0
2 years ago
A basketball player grabbing a rebound jumps 76.0 cm vertically. How much total time (ascent and descent) does the player spend.
MatroZZZ [7]

Answer: Part(a)=0.041 secs, Part(b)=0.041 secs

Explanation: Firstly we assume that only the gravitational acceleration is acting on the basket ball player i.e. there is no air friction

now we know that

a=-9.81 m/s^2  ( negative because it is pulling the player downwards)

we also know that

s=76 cm= 0.76 m ( maximum s)

using kinetic equation

v^2=u^2+2as

where v is final velocity which is zero at max height and u is it initial

hence

u^2=-2(-9.81)*0.76

u=3.8615 m/s\\

now we can find time in the 15 cm ascent

s=ut+0.5at^2

0.15=3.861*t+0.5*9.81t^2\\

using quadratic formula

t=\frac{-3.861+\sqrt{3.86^2-4*0.5*9.81(-0.15)} }{2*0.5*9.81}

t=0.0409 sec

the answer for the part b will be the same

To find the answer for the part b we can find the velocity at 15 cm height similarly using

v^2=u^2+2as

where s=0.76-0.15

as the player has traveled the above distance to reach 15cm to the bottom

v^2=0^2 +2*(9.81)*(0.76-0.15)

v=3.4595

when the player reaches the bottom it has the same velocity with which it started which is 3.861

hence the time required to reach the bottom 15cm is

t=\frac{3.861-3.4595}{9.81}

t=0.0409

8 0
2 years ago
An object is moving in a straight line along the y axis. As a function of time, its position is given by the equation y=3.0+4.8x
romanna [79]

Answer:

Explanation:

<u>Instant Velocity and Acceleration </u>

Give the position of an object as a function of time y(x), the instant velocity can be obtained by

v(x)=y'(x)

Where y'(x) is the first derivative of y respect to time x. The instant acceleration is given by

a(x)=v'(x)=y''(x)

We are given the function for y

y(x)=3.0+4.8x +6.4x^2

Note we have changed the last term to be quadratic, so the question has more sense.

The velocity is

v(x)=y'(x)=4.8+12.8x

And the acceleration is a(x)=v'(x)=12.8

5 0
3 years ago
14. Convert 22 degrees celsius to fahrenheit.<br> Please show your work
forsale [732]
(22°C × 9/5) + 32 = 71.6°F
6 0
3 years ago
Read 2 more answers
A point charge is placed 100 m from a 6 uC charge generating an electric field. What is the
kvv77 [185]

The strength of the electric field is 5 N/C

Explanation:

The magnitude of the electric field produced by a single-point charge is given by:

E=\frac{kQ}{r^2}

where

k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

Q is the magnitude of the charge

r is the distance from the charge

In this problem, we have:

Q=6 \mu C = 6\cdot 10^{-6}C is the charge producing the field

r = 100 m is the distance from the charge at  which we want to calculate the field

Substituting into the equation, we find the s trength of the electric field:

E=\frac{(8.99\cdot 10^9)(6\cdot 10^{-6})}{(100)^2}=5.4 N/C \sim 5 N/C

Learn more about electric field:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

3 0
3 years ago
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