Pluto has been reassigned and is now a dwarf planet. Why did scientists think this reassignment was necessary? If you were a sci
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The Young modulus E is given by:
where
F is the force applied
A is the cross-sectional area perpendicular to the force applied
is the initial length of the object
is the increase (or decrease) in length of the object.
In our problem,
is the initial length of the column, 
is the Young modulus. We can find the cross-sectional area by using the diameter of the column. In fact, its radius is:
and the cross-sectional area is
The force applied to the column is the weight of the load:
Now we have everything to calculate the compression of the column:
So, the column compresses by 1.83 millimeters.
where
F is the force applied
A is the cross-sectional area perpendicular to the force applied
In our problem,
and the cross-sectional area is
The force applied to the column is the weight of the load:
Now we have everything to calculate the compression of the column:
So, the column compresses by 1.83 millimeters.
Answer:
v = 27.28 m /s, θ = 63.9º
Explanation:
For this exercise we can approximate the movement to a projectile launch, let's analyze the situation.
* We must find the horizontal speed, for this we will find the descent time and the horizontal distance
* We look for the vertical speed
At the highest point the speed is horizontal
Let's find the time it takes for the kite to reach the ground
y = y₀ + v_{oy} t - ½ g t²
0 =y₀ + 0 -1/2 gt²
t =
t = √(2 40/32)
t = 2.5 s
to find the horizontal velocity we must know the horizontal distance, let's use trigonometry
sin θ = y / l
θ = sin⁻¹1 y / l
θ = sin⁻¹ 40/50
θ = 53.1º
therefore the horizontal distance is
x = l cos 53.1
x = 50cos 53.1
x = 30 m
let's use the equation
x = v₀ₓ t
v₀ₓ = x / t
v₀ₓ = 30 / 2.5
v₀ₓ = 12 m / s
we look for the vertical component of the velocity
v_y = v_{oy} - g t
v_y = 0 - g t
v_y = - 9.8 2.5
v_y = -24.5 m / s
the negative sign indicates that the speed is directed downwards, because it is the arrival point, as they indicate that there is no friction, the exit speed is the same, worse with the opposite sign
We already have the two components of the velocity, let's use the Pythagorean theorem to find the modulus
v =
v =
v = 27.28 m /s
we use trigonometry for the angle
tan θ = v_y / vₓ
θ = tan⁻¹ v_y / vₓ
θ = tan⁻¹ 24.5 / 12
θ = 63.9º
Answer: +2.10V
Explanation:
Using Nernst equation :
where,
= standard emf for the cell = +2.20 V
n = number of electrons in oxidation-reduction reaction = 6
= emf of the cell = ?
= concentration =
= concentration =
Now put all the given values in the above equation, we get:
The standard emf for the cell using the overall cell reaction below is +2.10 V