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Marina CMI [18]
3 years ago
15

Pluto has been reassigned and is now a dwarf planet. Why did scientists think this reassignment was necessary? If you were a sci

entist at that time, would you be for or against the reassignment of Pluto? What evidence would you give to defend your choice?
Physics
2 answers:
nadya68 [22]3 years ago
7 0
I would not because Pluto is like the other planets even though that it is smaller that all the other planets and colder but I don’t think it was necessary
kap26 [50]3 years ago
6 0

Answer:

Explanation:

we humans have our own ify classification for celestial objects, most people are saddened that pluto is not a planet anymore altho it hasn't changed at all.

scientist say that if an object is going to be considered a planet it must fill in these three checkboxes:

You must be spherical, you must orbit a star, and you must have already cleared your path or debris.

Pluto fills in the first two boxes but it does orbit in the keyperbelt and there are 5 other objects just like it. this is why pluto has been dubbed a dwarf planet.

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In a city park a nonuniform wooden beam 5.00 m long is suspended horizontally by a light steel cable at each end. The cable at t
DanielleElmas [232]

Answer:

Explanation:

System of forces in balance

ΣFx = 0

ΣFy = 0

∑MA = 0

MA = F*d

Where:

∑MA  : Algebraic sum of moments in the the point (A)

MA : moment in the point A ( N*m)

F  : Force ( N)

d  : Horizontal distance of the force to the point A ( N*m

Forces acting on the beam

T₁ = 620 N : Tension in cable 1 ,at angle of 30° with the vertical on the left

T₂ : Tension in cable 2, at angle of 50.0° with the vertical on the right.

W : Weight of the beam

x-y T₁ and T₂ components

T₁x= 620*sin30° = 310 N

T₁y= 620*cos30° = 536.94 N

T₂x= T₂*sin50°

T₂y= T₂*cos50°

Calculation of the T₂

ΣFx = 0  

T₂x-T₁x = 0

T₂x=T₁x

T₂*sin50° =  310 N

T₂ =  310 N /sin50°

T₂ = 404.67 N

Calculation of the W

ΣFy = 0  

T₂y+T₁y-W = 0

(404.67) *cos50° +  536.94 = W

W= 260.12+ 536.94

W= 797.06 N

Location of the center of gravity of the beam

∑MA = 0 , point (A) (point where the  cable 2  of the right is located on the beam)

T₁y(5)-W(d) = 0

T₁y(5) = W(d)

d = T₁y(5)/W

d =  536.94(5) / 797.06

d = 3.37m

The center of gravity is located at 3.37m measured from the right end of the beam

5 0
3 years ago
A sound wave of wavelength 0.682 m and velocity 325 m/s is produced for 0.500 s. what is the frequency
Naya [18.7K]
Recall that given the velocity and wavelength, frequency can be computed as

frequency =  \frac{speed}{wavelength}
Substituting the given values, we have
frequency =  \frac{325 m/s}{0.682 m}  \\ frequency = 477 Hz

Answer: 477 Hz
6 0
4 years ago
A piece of rocky debris in space has a semi major axis of 45.0 AU. What is its orbital period?
KATRIN_1 [288]

Complete Question

Planet D has a semi-major axis = 60 AU and an orbital period of 18.164 days. A piece of rocky debris in space has a semi major axis of 45.0 AU.  What is its orbital period?

Answer:

The value  is  T_R  = 11.8 \  days  

Explanation:

From the question we are told that

   The semi - major axis of the rocky debris  a_R = 45.0\  AU

   The semi - major axis of  Planet D is  a_D  = 60 \  AU

    The orbital  period of planet D is  T_D = 18.164 \  days

Generally from Kepler third law

          T \  \ \alpha \ \ a^{\frac{3}{2} }

Here T is the  orbital period  while a is the semi major axis

So  

        \frac{T_D}{T_R}  =  \frac{a^{\frac{3}{2} }}{a_R^{\frac{3}{2} }}

=>     T_R  = T_D *  [\frac{a_R}{a_D} ]^{\frac{3}{2} }  

=>     T_R  = 18.164  *  [\frac{ 45}{60} ]^{\frac{3}{2} }

=>      T_R  = 11.8 \  days  

   

7 0
3 years ago
This is a group of elements with few valence electrons that conducts heat and electricity.
k0ka [10]

Answer:

Metals

Explanation:

The group of elements with few valence electrons that conducts heat and electricity is known metals. Metals are good conductors of heat and electricity. The outer electrons in metals are loosely bound to the atom and are thus able to freely move around and conduct electricity and heat.

5 0
4 years ago
A constant force of 5KN pulls a crate along a distance of 15 m in 75s.What is the power​
xxMikexx [17]

Explanation:

We know,

1KN = 1000N

Then, Force(F) = 5*1000N

=5000N

Here,

Power (P)=Work(W)/Time(T)

=Force * distance/ Time (W = F*s)

= 5000*15/75

=1000

So, The power of body or object is 1000Watt.

I hope this will be helpful for you.

8 0
4 years ago
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