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Sladkaya [172]
3 years ago
6

Which of the following electrons emits the most energy?

Physics
1 answer:
AveGali [126]3 years ago
8 0

In the atom, the nucleus is charged positive and the electron is charged
negative.  So we know that they're attracted to each other.  It takes energy
to keep the electron from falling into the nucleus.

-- If you want to drag the electron farther out from the nucleus, you have to
do work on it ... put energy in to it.

-- When the electron loses energy, it falls in closer to the nucleus. The more
energy it loses, the closer to the nucleus it falls.

-- From the list of choices in the question, the <span>electron moving <em>two energy levels </em>
<em>closer to the nucleus</em> loses more energy than any other choice.

</span> 
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3 years ago
What is the change in potential energy if the distance separating the electron and proton is increased to 1.0 nm?
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Answer:

Ep=-2.3*10^{-19}J

Explanation:

The change in potential energy can be expressed as:

Ep=K.\frac{q1.q2}{r}

where K is a constant with a value of 9*10^{9}\frac{N.m^{2}}{C^{2}}, q1 and q2 are the charges of the proton and the electron and r is the distance between them.

The charge for the proton is +1.6*10^{-19}C and the charge for the electron is -1.6*10^{-19}C.

Converting r=1.0nm to m:

1.0nm*\frac{1*10^{-9}m}{1.0nm}=1*10^{-9}m

Replacing values:

Ep=9*10^{9}\frac{N.m^{2}}{C^{2}}.\frac{(+1.6*10^{-19}C).(-1.6*10^{-19}C)}{1*10^{-9}m}

Ep=-2.3*10^{-19}J

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2 years ago
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