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3 years ago

Which of the following electrons emits the most energy?

1 answer:

8 0

In the atom, the nucleus is charged positive and the electron is charged
negative. So we know that they're attracted to each other. It takes energy
to keep the electron from falling into the nucleus.

-- If you want to drag the electron farther out from the nucleus, you have to
do work on it ... put energy in to it.

-- When the electron loses energy, it falls in closer to the nucleus. The more
energy it loses, the closer to the nucleus it falls.

-- From the list of choices in the question, the electron moving two energy levels 
closer to the nucleus loses more energy than any other choice.

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If the absolute temperature of a gas is 600 K, the temperature in degrees Celsius is: A. 705Â°C. B. 873Â°C. C. 273Â°C. D. 327Â°C

zlopas [31]

Answer:

D). $327 ^0 C$

Explanation:

As we know that temperature scale is linear so we will have

$\frac{^0C - 0}{100 - 0} = \frac{K - 273}{373 - 273}$

now we have

$\frac{^0 C - 0}{100} = \frac{K - 273}{100}$

so the relation between two scales is given as

$^0 C = K - 273$

now we know that in kelvin scale the absolute temperature is 600 K

so now we have

$T = 600 - 273 = 327 ^0 C$

so correct answer is

D). $327 ^0 C$

4 0

3 years ago

Water is completely filling black metallic vessel having cubic form and thin walls. The mass of water is 1 kg and initial temper

Brilliant_brown [7]

Answer:

Check the attached image

Explanation:

To solve the problem for time you will have to use the formula for time, t = d/s which means time equals distance divided by speed.

Kindly check the attached image below for the step by step explanation to the question.

5 0

3 years ago

A block of ice of mass 4.30 kg is placed against a horizontal spring that has a force constant k = 250 N/m and is compressed a d

OleMash [197]

Answer:

W = 0.060 J

v_2 = 0.18 m/s

Explanation:

solution:

for the spring:

W = 1/2*k*x_1^2 - 1/2*k*x_2^2

x_1 = -0.025 m and x_2 = 0

W = 1/2*k*x_1^2 = 1/2*(250 N/m)(-0.028m)^2

W = 0.060 J

the work-energy theorem,

W_tot = K_2 - K_1 = ΔK

with K = 1/2*m*v^2

v_2 = √2*W/m

v_2 = 0.18 m/s

8 0

3 years ago

A child wearing socks is trying to see how far he can slide across his kitchen floor. If

Ugo [173]

Answer:

The coefficient of static friction between the ground and the soles of a runner’s shoes is 0.98. What is the maximum speed in which the runner can accelerate without slipping if they have a mass of 73 kg?

Explanation:

3 0

3 years ago

Each plate of a parallel‑plate capacitor is a square of side 4.19 cm, 4.19 cm, and the plates are separated by 0.407 mm. 0.407 m

alexandr1967 [171]

Answer:

The electric field strength inside the capacitor is 49880.77 N/C.

Explanation:

Given:

Side length of the capacitor plate (a) = 4.19 cm = 0.0419 m

Separation between the plates (d) = 0.407 mm = $0.407\times 10^{-3}\ m$

Energy stored in the capacitor (U) = $7.87\ nJ=7.87\times 10^{-9}\ J$

Assuming the medium to be air.

So, permittivity of space (ε) = $8.854\times 10^{-12}\ F/m$

Area of the square plates is given as:

$A=a^2=(0.0419\ m)^2=1.75561\times 10^{-3}\ m^2$

Capacitance of the capacitor is given as:

$C=\dfrac{\epsilon A}{d}\\\\C=\frac{8.854\times 10^{-12}\ F/m\times 1.75561\times 10^{-3}\ m^2 }{0.407\times 10^{-3}\ m}\\\\C=3.819\times 10^{-11}\ F$

Now, we know that, the energy stored in a parallel plate capacitor is given as:

$U=\frac{CE^2d^2}{2}$

Rewriting in terms of 'E', we get:

$E=\sqrt{\frac{2U}{Cd^2}}$

Now, plug in the given values and solve for 'E'. This gives,

$E=\sqrt{\frac{2\times 7.87\times 10^{-9}\ J}{3.819\times 10^{-11}\ F\times (0.407\times 10^{-3})^2\ m^2}}\\\\E=49880.77\ N/C$

Therefore, the electric field strength inside the capacitor is 49880.77 N/C

8 0

3 years ago