Answer:
46 dgres is the answer
Explanation:
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Answer:
B = 4.5 x 10⁻⁷ T = 0.45 μT
Explanation:
From Ampere's law the magnetic field at a certain radius from straight current-carrying wire is given by the following formula:
where,
B = magnetic field = ?
= permeability of free space = 4π x 10⁻⁷ H/m
I = current = 180 A
r = radius = 80 m
Therefore,
<u>B = 4.5 x 10⁻⁷ T = 0.45 μT</u>
Answer:
Explanation:
According to Newton's second law, the tension in the string is equal to the centripetal force, since the mass is under an uniform circular motion:
Here is the centripetal acceleration, which is defined as:
So, replacing:
In this case we have , and . Thus, the tension required to mantain uniform circular motion is:
Answer:
x(spring stretch)=1.74×10⁻³ meter
Explanation:
Given Data
l (length)=0.175 m
v (speed)= 3.86 m/s
x₁(stretch)=0.0140 m
x(spring stretch)=?
Solution
Centripetal force=Spring Constant
as
Spring force = gravitational force
Answer:
Vf = - 20 m/s ( -ve sign shows that the particle is moving opposite to positive x- direction).
Explanation:
Given:
Vi = 20 m/s, m= 10 mg =1 × 10⁻⁵ kg, q= -4.0 × 10⁻⁶ C , E= 20 N/C. t= 5.0 s
first to find Electric Force
F= Eq = 20 × -4.0 10⁻⁶ C = - 8 × 10⁻⁵ N (-ve sign shows that the field will push the particle opposite to positive x- direction)
We also have F=ma
⇒ a = F/m = - 8 × 10⁻⁵ N / 10 × 10⁻⁵ kg = -8 m/s² ( -ve sign shows that the particle is accelerated opposite to positive x- direction)
Now according the first equation of Motion.
Vf = Vi + at
Vf = 20 m/s + -8 m/s² × 5 s
Vf= -20 m/s ( -ve sign shows that the particle is moving opposite to positive x- direction)