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katen-ka-za [31]
3 years ago
9

1. Use the periodic table to determine which of the following groups of elements would have properties most similar to arsenic (

As)
A . Boron (B) , silicon (Si) , and germanium (Ge)

B. Nitrogen (N), Phosphorous (P) , and antimony (Sb)

C. Germanium (Ge) , selenium (Se) , and bromide (Br)

D. Gallium (Ga) , germanium (Ge) , and selenium (Se)

Physics
1 answer:
Sliva [168]3 years ago
6 0

Answer:

D

Explanation:

<u>The correct answer would be option D.</u>

Gallium (Ga) , germanium (Ge) , selenium (Se) , and arsenic (AS) all belong to the same group of elements referred to as the transition elements. The transition elements have partially-filled d orbital, a feature that confers some characteristic properties on the elements or their ions. These properties include:

  • <em> variable oxidation state of </em>
  • <em>formation of colored ions and compounds</em>
  • <em>catalytic property</em>
  • <em>paramagnetic compounds</em>
  • <em>etc.</em>

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Gravitational force on the moon is only 1/6 that of the gravitational force on earth. what would be the weight of a 10-kg object
MA_775_DIABLO [31]
According to Newton's Second Law of Motion, the force is equal to the mass of an object multiplied by its acceleration. When you talk about gravitational force, the acceleration referred to here is the acceleration due to gravity. This is very familiar to us in physics. The acceleration due to gravity on Earth is equal to 9.81 m/s². It actually depends on the location. According to the Universal Law of Gravitation:

F = Gm₁m₂/d²

The force is a factor of the product of two masses and their distance from each other. The G is a constant called the universal gravitational constants. So, gravitational force is actually a relative force exerted by one body to another. 

Going back the Second Law of Motion, we can modify the equation to:

F = mg

Since it is mentioned that the gravity on the moon is only 1/6 of the Earth, then the gravity for moon is:
g,moon = 1/6(9.81) = 1.635 m/s²
So, let's compare the weight of the object with a mass of 10 kg. The weight is actually the force due to gravity pulling you towards the center of the body.

Weight on Earth = (10 kg)(9.81 m/s²) = 98.1 N
Weight on Moon = (10 kg)(1.635 m/s²) = 16.35 N

The mass, on the other hand, is not affected by gravity. It is always constant. Therefore, the mass of the object on the moon is the same with its mass on the Earth.
6 0
4 years ago
Liquid flows through a 4.0 cm diameter pipe at 1.0 m/s. there is a 2.0 cm diameter restriction on the line. what is the velocity
Vanyuwa [196]
To determine the velocity in the restriction, we need to remember the law of conservation of mass where mass in should be equal to the mass out since mass cannot be created or destroyed. For this system, mass flow rate in is equal to mass flow rate out. We do as follows:

Mass flow rate in = Mass flow rate out
density (volumetric flow rate in) = density (volumetric flow rate out)

Since the liquid in and out are the same, then density would be cancelled.
(volumetric flow rate in) = (volumetric flow rate out)
Area in x velocity in = Area out x velocity out
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3 years ago
Many students use earbuds or headphones while working on a computer or listening to music. Electromagnetics are within the liste
Katyanochek1 [597]

Answer:

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Explanation:

8 0
3 years ago
A 500kg elevator is raised to a height of 10 m in 10 seconds. Calculate the power of the motor.
Hunter-Best [27]

Answer:

Correct answer: Third statement  P = 4900 W

Explanation:

Given:

m = 500 kg  the mass of the elevator

h = 10 m  reached height after t = 10 seconds

P = ? power of the motor

The formula for the calculating power of the motor is:

P = W / t

since work is a measure of change in this case of potential energy then it is:

W = ΔEp = Ep - 0 = Ep

In this case we must take g = 9.81 m/s²

Ep = m g h = 500 · 9.81 · 10 = 49,050 W ≈ 49,000 W

Ep ≈ 49,000 W

P = Ep / t = 49,000 / 10 = 4,900 W

P =4,900 W

God is with you!!!

3 0
4 years ago
A ship’s wheel is rotated 128 degrees. Its radius is 22 cm. How far would a point on the wheel’s edge move in this rotation?
ZanzabumX [31]
To solve this problem, we use this formula:
s = rθ

where
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r is the radius of the circle or the wheel
θ is the subtended angle or the angle of rotation of the wheel

Plugging in the given values and converting degrees to radians
s = 22 *128 (π/180)
s = 49.15 cm
7 0
3 years ago
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