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tekilochka [14]
3 years ago
15

Suppose that you take a 10 kg mass on the surface of the earth and then place it on the moon. What will

Physics
1 answer:
sergey [27]3 years ago
5 0

Answer:

10 kg

Explanation:

The mass of an object does not change even if the amount of gravtiy changes.

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A roller coaster uses 800 000 J of energy to get to the top of the first hill. During this climb, it gains 500 000 J of potentia
Zarrin [17]

Answer:

<em>Good Luck!</em>

Explanation:

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2 years ago
A major contemporary learning view of personality which holds that personality traits result from a
DIA [1.3K]

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21

Explanation:

21 is x because 211211 1 1 1 1  1aghh

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3 years ago
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It is epistemically possible that a completed physics might include which of the following propositions? O Souls and other spiri
ohaa [14]

Answer:

option D.

Explanation:

The correct answer is option D.

At present the knowledge of physics does not includes the study related to souls , other spiritual substance.

Physics does not give the answers of question like God created universe , matter is unreal, etc.

So, there might will be possibility that in future complete physics will give the answer of all these questions i.e. correct answer is All of the above.

3 0
3 years ago
A 360-N child is in a swing that is attached to a pair of ropes 1.90 m long. Find the gravitational potential energy of the chil
Igoryamba

Answer:

684J

Explanation:

So basically the formula for gravitational potential energy is Mass X Gravity X height. That is G.p.e = mgh

We don't have the mass but since we have the height, we multiply directly with the height since the quantity of weight is already given.

so G.p.e = 360 X 1.9 = 684J

Note that; The answer is in joules because g.p.e is work done.

Hope that was helpful!!

7 0
3 years ago
A fixed 11.2-cm-diameter wire coil is perpendicular to a magnetic field 0.53 T pointing up. In 0.10 s , the field is changed to
Karolina [17]

Answer:

The average induced emf in the coil is 0.0286 V

Explanation:

Given;

diameter of the wire, d = 11.2 cm = 0.112 m

initial magnetic field, B₁ = 0.53 T

final magnetic field, B₂ = 0.24 T

time of change in magnetic field, t = 0.1 s

The induced emf in the coil is calculated as;

E = A(dB)/dt

where;

A is area of the coil = πr²

r is the radius of the wire coil = 0.112m / 2 = 0.056 m

A = π(0.056)²

A = 0.00985 m²

E = -0.00985(B₂-B₁)/t

E = 0.00985(B₁-B₂)/t

E = 0.00985(0.53 - 0.24)/0.1

E = 0.00985 (0.29)/ 0.1

E = 0.0286 V

Therefore, the average induced emf in the coil is 0.0286 V

3 0
3 years ago
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