Find the wavelength of the third line in the lyman series, and identify the type of em radiation.
1 answer:
The wavelength of the third line in the Lyman series, and identify the type of EM radiation
In this series, the spectral lines are obtained when an electron makes a transition from any high energy level (n=2,3,4,5... ). The wavelength of light emitted in this series lies in the ultraviolet region of the electromagnetic spectrum.
1 / lambda = R(h)* ( -
)
= 109678 ( -
)
= 109678 (8/9)
Lambda = 9 / (109678 * 8 )
= 102.6 * m = 102.6 nm
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Formula used for transformer is:
Where:N1 = number of turns on primary coilN2 = number of turns on secondary coilV1 = voltage on primary coilV2 = voltage on secondary coil
In a step-down transformer primary coil has more turns than secondary coil. So the ratio 1:38 means that for each turn on secondary coil we have 38 turns on primary coil.
We can solve the equation for V2:
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