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1 year ago

Find the wavelength of the third line in the lyman series, and identify the type of em radiation.

Physics

1 answer:

Natalija [7]1 year ago

8 0

The wavelength of the third line in the Lyman series, and identify the type of EM radiation

In this series, the spectral lines are obtained when an electron makes a transition from any high energy level (n=2,3,4,5... ). The wavelength of light emitted in this series lies in the ultraviolet region of the electromagnetic spectrum.

1 / lambda = R(h)* ( $\frac{1}{(n1)^{2} }$ - $\frac{1}{(n2)^{2} }$ )

= 109678 ( $\frac{1}{1^{2} }$ - $\frac{1}{3^{2} }$ )

= 109678 (8/9)

Lambda = 9 / (109678 * 8 )

= 102.6 * $10^{-9}$ m = 102.6 nm

To learn more about Lyman series here

brainly.com/question/5762197

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4 years ago

Read 2 more answers

VP 3.12.1 Part APart complete A cyclist going around a circular track at 10.0 m/s has a centripetal acceleration of 5.00 m/s2. W

viktelen [127]

Answer:

A) r = 20.0 m

B) T = 41.6 s

C) = 6.1 m/s²

Explanation:

The centripetal acceleration is the one that explains that even though the cyclist is moving at a constant speed, his velocity is changing the direction all the time, keeping him around a circle.
This acceleration can be expressed as follows:

$a_{c} =\frac{v^{2}}{r} = \frac{(10.0m/s)^{2}}{r} = 5.00 m/s2 (1)$

Solving for r:

$r = \frac{v^{2}}{a_{c} } = \frac{(10.0m/s)^{2}}{5.00m/s2} = 20.0 m (2)$

We can apply the definition of linear velocity, remembering that the period is the time needed to complete an entire circle (T).
The arc around a circumference (the distance traveled) , is just 2*π*r, so applying the definition of linear velocity, we can write the following expression:

$v = \frac{\Delta s}{\Delta t} = \frac{2*\pi*r}{T} (3)$

Solving for T:

$T = \frac{\Delta s}{v} = \frac{2*\pi*r}{v} = \frac{2*\pi*265m}{40.0m/s} =41.6 s (4)$

The centripetal acceleration of the car from B) can be found as follows:

$a_{c} =\frac{v^{2}}{r} = \frac{(40.0m/s)^{2}}{265m} = 6.1 m/s2 (5)$

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3 years ago

Calculate the ratio of the resistance of 12.0 m of aluminum wire 2.5 mm in diameter, to 30.0 m of copper wire 1.6 mm in diameter

alukav5142 [94]

Answer: 0.258

Explanation:

The resistance $R$ of a wire is calculated by the following formula:

$R=\rho\frac{l}{s}$ (1)

Where:

$\rho$ is the resistivity of the material the wire is made of. For aluminium is $\rho_{Al}=2.65(10)^{-8}m\Omega$ and for copper is $\rho_{Cu}=1.68(10)^{-8}m\Omega$