Question

Find the wavelength of the third line in the lyman series, and identify the type of em radiation.

Answer 1

The wavelength of the third line in the Lyman series, and identify the type of EM radiation

In this series, the spectral lines are obtained when an electron makes a transition from any high energy level (n=2,3,4,5... ). The wavelength of light emitted in this series lies in the ultraviolet region of the electromagnetic spectrum.

1 / lambda = R(h)* ( $\frac{1}{(n1)^{2} }$ -   $\frac{1}{(n2)^{2} }$)

                 = 109678 ( $\frac{1}{1^{2} }$ -  $\frac{1}{3^{2} }$ )

                 = 109678 (8/9)

   Lambda = 9 / (109678 * 8 )

                  = 102.6 * $10^{-9}$ m = 102.6 nm

To learn more about Lyman series here

brainly.com/question/5762197

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