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valentinak56 [21]
3 years ago
7

NH

Biology
1 answer:
galina1969 [7]3 years ago
3 0

Answer:

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Nata [24]

Answer:

A if not A then its D

Explanation:

Mrk me branliest PLZZZZZZZZZ

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2 years ago
Explain how limiting factor may affect your terrarium​
Tpy6a [65]

Answer:

A limiting factor is anything that constrains a population's size and slows or stops it from growing. Some examples of limiting factors are biotic, like food, mates, and competition with other organisms for resources. Others are abiotic, like space, temperature, altitude, and amount of sunlight available in an environment. Limiting factors are usually expressed as a lack of a particular resource. For example, if there are not enough prey animals in a forest to feed a large population of predators, then food becomes a limiting factor. Likewise, if there is not enough space in a pond for a large number of fish, then space becomes a limiting factor. There can be many different limiting factors at work in a single habitat, and the same limiting factors can affect the populations of both plant and animal species. Ultimately, limiting factors determine a habitat's carrying capacity, which is the maximum size of the population it can support.

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https://www.nationalgeographic.org/topics/limiting-factors/?q=&page=1&per_page=25

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Kingdom of organisms that have cell walls and chloroplast
just olya [345]

I only know that it sounds like a plant cell which is a eukaryotic cell.

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3 years ago
Which event might disrupt a stable ecosystem?
mel-nik [20]
An invasive species.
7 0
3 years ago
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During typical urination, a man releases about 400 mL of urine in about 30 seconds through the urethra, which we can model as a
Crazy boy [7]

Answer:

The flow speed in the urethra is 3.77 m/s

Explanation:

The flow rate or speed of a liquid is a measure of the volume of liquid that flows in a given amount of time.

Fluid flow rate, Q = area of the pipe or channel × velocity of the liquid

Q = A × v ; where Q is  in m³/s or L/s; A is in m²; velocity, v = is in m/s

Also flow rate, Q = volume/time

volume, V, is in m³ and time is in seconds

therefore, V/t = A × v

v = At / V

Volume, V = 400 mL = 0.4 L = 4 × 10⁻⁴ m³

Area, A, of tube = πr², where r is radius in meters

r = 4 mm = 4 × 10⁻³ m

A = 22/7 × (4 × 10⁻³ m)²

therefore, v = {22/7 × (4 × 10⁻³ m)² × 30}/4 × 10⁻⁴ m³

v = 3.77 m/s

Therefore, the flow speed in the urethra is 3.77 m/s

6 0
3 years ago
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