<img src="https://tex.z-dn.net/?f=%28%5Cfrac%7B3%7D%7B2%7D%20-%5Cfrac%7B1%7D%7B1%7D%20%29-%285%2B%5Cfrac%7B1%7D%7B1%7D%20%29%3D"

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3 years ago

id="TexFormula1" title="(\frac{3}{2} -\frac{1}{1} )-(5+\frac{1}{1} )=" alt="(\frac{3}{2} -\frac{1}{1} )-(5+\frac{1}{1} )=" align="absmiddle" class="latex-formula">

Help plz (Me ajuda)

Mathematics

2 answers:

Andrew [12]3 years ago

7 0

Your answer would be -11/2 and a alternate form would be -5 1/2 or -5.5

IgorLugansk [536]3 years ago

5 0

The answer can be either of the numbers followed:
-11/2
-5 1/2
-5.5

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Triss [41]

Answer:

Usual, because the result is between the minimum and maximum usual values.

Step-by-step explanation:

To identify if the value is usual or unusual we're going to use the Range rule of thumbs which states that most values should lie within 2 standard deviations of the mean. If the value lies outside those limits, we can tell that it's an unusual value.

Therefore:

Maximum usual value: μ + 2σ

Minimum usual value: μ - 2σ

In this case:

μ = 153.1

σ = 18.2

Therefore:

Maximum usual value: 189.5

Minimum usual value: 116.7

Therefore, the value of 187 lies within the limits. Therefore, the correct option is D. Usual, because the result is between the minimum and maximum usual values.

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Jlenok [28]

Answer:

the second one

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Hello There!

The area of a triangle can be found using this formula

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An expression to represent ( w increased by 5 )

SashulF [63]

Answer:

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Step-by-step explanation:

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W plus the constant value increase

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