All categories

3 years ago

Which statement describes what happens when (4, 6) is reflected across the y-axis? Select all that apply:

Mathematics

2 answers:

Sonja [21]3 years ago

4 0

B)The x-coordinate of the reflection is -4.

Keith_Richards [23]3 years ago

3 0

Answer:

b) the x-coordinate of the reflection is -4

d) the reflection is in quadrant IV

Step-by-step explanation:

You might be interested in

If i divide 3/4 with 2/5 what would the answer be

Talja [164]

Answer:

The asnwer i fro 5/2 iss 2.5 and the other question is the answer is 1.3 is we add now is 3.8

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

I am having trouble. Help plz

Yuliya22 [10]

Area is calculated by multiplying length by width. Since we are given the width, we can test each length and see if the product matches the rectangle's area.

(2m - 3)(4m - 4) = 8m² - 20m + 12 ≠ 8m² + 4m - 12

(8m - 3)(4m - 4) = 32m² - 44m + 12 ≠ 8m² + 4m - 12

(2m + 3)(4m - 4) = 8m² + 4m - 12

(8m + 3)(4m - 4) = 32m² + 20m - 12 ≠ 8m² + 4m - 12

The length of the rectangle must be 2m + 3. Another method of solving this would be to divide the area by the width, or 8m² + 4m - 12 ÷ 4m - 4.

6 0

3 years ago

Which property justifies the following statement<br> If 13x=104,then x=8

Elena-2011 [213]

This is a a reflective property because it is an if then statement.

8 0

3 years ago

Consider the function f(x, y) = x2 + xy + y2 defined on the unit disc, namely, D = {(x, y)| x2 + y2 ≤ 1}. Use the method of Lagr

alex41 [277]

Answer:

Answer with explanation and steps are in the following attachment.

Step-by-step explanation:

6 0

3 years ago

Use vertical multiplication to find the product of:

Rom4ik [11]

Answer:

$x^6+x^4+4x^3-2x^2-x+3$

Step-by-step explanation:

$x^3+2x+3$

$\times(x^3-x+1)$

---------------------------------

First step multiply your terms in your first expression just to the 1 in the second expression like so:

$x^3+2x+3$

$\times(x^3-x+1)$

---------------------------------

$x^3+2x+3$ Anything times 1 is that anything.

That is, $(x^3+2x+3) \cdot 1=x^3+2x+3$ .

Now we are going to take the top expression and multiply it to the -x in the second expression. $-x(x^3+2x+3)=-x^4-2x^2-3x$ . We are going to put this product right under our previous product.

$x^3+2x+3$

$\times(x^3-x+1)$

---------------------------------

$x^3+2x+3$

$-x^4-2x^2-3x$

We still have one more multiplication but before we do that I'm going to put some 0 place holders in and get my like terms lined up for the later addition:

$x^3+2x+3$

$\times(x^3-x+1)$

---------------------------------

$0x^4+x^3+0x^2+2x+3$

$-x^4+0x^3-2x^2-3x+0$

Now for the last multiplication, we are going to take the top expression and multiply it to x^3 giving us $x^3(x^3+2x+3)=x^6+2x^4+3x^3$ . (I'm going to put this product underneath our other 2 products):