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Answer: 13.46 m/s
Explanation:
Initial velocity V1 = 5.82 m/s
acceleration A = 2.35m/s^2
Time taken T = 3.25s
Final velocity V2 = ?
Recall that acceleration is the rate of change of velocity per unit time i.e acceleration = (V2 - V1)/T
2.35m/s^2 = (V2 - 5.82 m/s) / 3.25s
cross multiply
2.35m/s^2 x 3.25s = (V2 - 5.82 m/s)
7.6375m/s = V2 - 5.82 m/s
V2 = 7.6375m/s + 5.82m/s
V2 = 13.46 m/s
Thus, the car final velocity is 13.46 m/s
Given :
One particle, of mass m , moves with a speed v in the x-direction, and another particle, of mass 2 m , moves with a speed v/2 in the y-direction.
To Find :
The velocity of the center of mass of these two particles.
Solution :
Speed of mass m, .
Speed of mass 2m , .
Speed of center of mass is given by :
Hence, this is the required solution.
Assuming that the collision is inelastic that is they are stuck together after the collision, momentum is conserved. We can determine the final velocity of the final mass as follows:
m1v1 + m2v2 = m3v3
100(4) + (200)(-3) = (300)v3
v3 = -0.6667 m/s
Therefore, the final mass moves at 0.6667 m/s to the left.
Answer:
Induced emf in the loop is 0.02208 volt.
Induced current in the loop is 0.0368 A.
Explanation:
Given that,
Area of the single loop,
The initial value of uniform magnetic field, B = 3.8 T
The magnetic field is decreasing at a constant rate,
(a) The induced emf in the loop is given by the rate of change of magnetic flux.
(b) Resistance of the loop is 0.6 ohms. Let I is the current induced in the loop. Using Ohm's law :
Hence, this is the required solution.