I will give brainliest) According to Newton's second law of motion, when an object is acted on by an unbalanced force, how will
2 answers:
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The strength of the gravitational field is given by:
where
G is the gravitational constant
M is the Earth's mass
r is the distance measured from the centre of the planet.
In our problem, we are located at 300 km above the surface. Since the Earth radius is R=6370 km, the distance from the Earth's center is:
And now we can use the previous equation to calculate the field strength at that altitude:
And we can see this value is a bit less than the gravitational strength at the surface, which is
.
where
G is the gravitational constant
M is the Earth's mass
r is the distance measured from the centre of the planet.
In our problem, we are located at 300 km above the surface. Since the Earth radius is R=6370 km, the distance from the Earth's center is:
And now we can use the previous equation to calculate the field strength at that altitude:
And we can see this value is a bit less than the gravitational strength at the surface, which is
Explanation :
It is given that,
In the given figure all the three resistors are in series.
Current flowing in the circuit,
Voltage,
We know that in series circuit the current flowing in all resistors is same.
Using Ohm's law, we get:
Hence, this is the required solution.