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Elza [17]
3 years ago
8

Identical marbles are released from the same height on each of the following four frictionless ramps . Compare the speed of the

marbles at the end of each ramp. Explain your reasoning
Physics
1 answer:
Montano1993 [528]3 years ago
3 0

Since there is no friction on the ramp so there is no loss of energy in terms of frictional loss

So here we can use mechanical energy conservation law in this case

so here we will have

U_i = KE_f

here we know that

U_i = mgh

also we know that

K_f = \frac{1}{2}mv^2

now we will have

mgh = \frac{1}{2}mv^2

now by solving above equation we have

v = \sqrt{2gh}

so here as we know all identical balls are released from same height so all balls must have same speed at the end

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Answer:

a. 4.5secs

Explanation:

From the question, the equation describing the height is given by

h(t)=320-16t^{2}\\

at the point when the rock hit the ground, the height,h will be zero.

Hence we can have

h(t)=320-16t^{2}\\\\at  h(t)=0\\0=320-16t^{2}\\hence \\320=16t^{2}\\t^{2}=\frac{320}{16}\\ t^{2}=20\\t=\sqrt{20}\\ t=4.47secs\\t=4.5sec\\

hence the rock will hit the ground in 4.5secs

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