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Fed [463]
3 years ago
15

A 50-foot ladder leans against a building. If the base of the ladder is 6 feet from the base of the building, what is the angle

formed by the ladder and the building?

Mathematics
1 answer:
adell [148]3 years ago
4 0

Answer:

The angle between the building and the ladder \theta = 6.9°

Step-by-step explanation:

Given data

AB = 50 ft = length of the building

BC = 6 ft

\theta = Angle between the ladder & building

From Δ ABC

\sin \theta = \frac{BC}{AB}

\sin \theta= \frac{6}{50}

\theta = 6.9°

This is the angle between the building and the ladder.

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I will give you 100 points if you can answer this<br><br> (66×578)÷3368=55÷77=???
erma4kov [3.2K]
(66✖️578) ➗ 3368=55➗77

P parentheses
E exponents
M multiplication
D division
A addition
S subtraction

You would do (66✖️578) first since it is in parentheses
66✖️578=38,148

38,138➗3368=55➗77
Since there are no exponents or multiplication you would do division

38,138➗3368= 11.3236342
55➗77=0.7

11.32 does not equal 0.7
So this equation would be false

Hope this helps! :3








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