Answer:
The smallest integer is -4.
Step-by-step explanation:
Let the smallest integer be x.
Since the integers are all multiples of 4, they are
=> x, x+4, x+8, x+12 and x+16
=> x + x+4 + x+8 + x+12 + x+16 = 20
=> 5x + 40 = 20
Subtract 40 from both sides of the equation
5x +40 - 40 = 20 - 40
5x = -20
Divide both sides by the coefficient of x(which is 5)
x = -4
∴ the smallest integer is -4.
Hope this helps!!!
For the first question, simply find a point that is on the line segment. For the second question, knowing that in quadrant iii the x values are negative and the y values are also positive using this fact find the point that has x negative and y positive.
1: 14 ft
2: 18
3: 11; 28
4: 8; 96
5: a = 5x3
6: a = 8x8
7: 1x42, 2x21, 3x14, and 6x7. 6x7 probably makes the most sense.
Step-by-step explanation:
y=-27
...................
Answer:
x≥−8
Step-by-step explanation:
Step 1: Simplify both sides of the inequality.
−4x−6≤26
Step 2: Add 6 to both sides.
−4x−6+6≤26+6
−4x≤32
Step 3: Divide both sides by -4.
−4x/−4 ≤ 32/−4
x≥−8
