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Citrus2011 [14]
2 years ago
7

Express p in terms of q if

Mathematics
1 answer:
Irina-Kira [14]2 years ago
8 0

p=x^2+\dfrac{1}{x^2}\\\\p=\dfrac{x^4}{x^2}+\dfrac{1}{x^2}\\\\p=\dfrac{x^4+1}{x^2}\qquad(*)

q=x+\dfrac{1}{x}\\\\q=\dfrac{x^2}{x}+\dfrac{1}{x}\\\\q=\dfrac{x^2+1}{x}\qquad\text{square both sides}\\\\q^2=\left(\dfrac{x^2+1}{x}\right)^2\\\\q^2=\dfrac{(x^2+1)^2}{x^2}\qquad\text{use}\ \ (a+b)^2=a^2+2ab+b^2\\\\q^2=\dfrac{(x^2)^2+2(x^2)(1)+1^2}{x^2}\\\\q^2=\dfrac{x^4+2x^2+1}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+\dfrac{2x^2}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+2\qquad\text{subtract 2 from both sides}\\\\q^2-2=\dfrac{x^4+1}{x^2}\\\\\text{From (*) we have}\\\\\boxed{p=q^2-2}

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Step-by-step explanation:

You can find the amount of students each vehicle can carry by representing the two scenarios in equations.

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High school A used 1 van and 6 buses, so there will be 1"v" and 6"b" for 372 students.

High school B used 4 vans and 12 buses, so there will be 4"v" and 12"b" for 780 students.

Now, represent these in equations:

v+6b = 372\\4v + 12b = 780

We can use substitution to solve this system:

v + 6b = 372 can be rewritten as v = 372 - 6b after subtracting 6b from both sides. You can then substitute this new value of "v" into the other equation to solve for "b":

4(372-6b) + 12b = 780\\1488 - 24b + 12b = 780\\1488 - 12b = 780\\-12b = -708\\b = 59

After solving for b, you can then substitute the new value of b into the other equation to find the value of v:

v + 6(59) = 372\\v + 354 = 372\\v = 18

After solving for both variables, you find that each bus can hold 59 students and each van can hold 18 students.

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3 years ago
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set up a proportion, 59/140= x/300. Cross multiply: 140x= 17700. Then divide both sides by 140. the answer is 126.42857... ore rounded, 126.

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3 years ago
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