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2 years ago

Express p in terms of q if

Mathematics

1 answer:

Irina-Kira [14]2 years ago

8 0

$p=x^2+\dfrac{1}{x^2}\\\\p=\dfrac{x^4}{x^2}+\dfrac{1}{x^2}\\\\p=\dfrac{x^4+1}{x^2}\qquad(*)$

$q=x+\dfrac{1}{x}\\\\q=\dfrac{x^2}{x}+\dfrac{1}{x}\\\\q=\dfrac{x^2+1}{x}\qquad\text{square both sides}\\\\q^2=\left(\dfrac{x^2+1}{x}\right)^2\\\\q^2=\dfrac{(x^2+1)^2}{x^2}\qquad\text{use}\ \ (a+b)^2=a^2+2ab+b^2\\\\q^2=\dfrac{(x^2)^2+2(x^2)(1)+1^2}{x^2}\\\\q^2=\dfrac{x^4+2x^2+1}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+\dfrac{2x^2}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+2\qquad\text{subtract 2 from both sides}\\\\q^2-2=\dfrac{x^4+1}{x^2}\\\\\text{From (*) we have}\\\\\boxed{p=q^2-2}$

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The sum of two numbers is 75. The second number is 3 less than twice the first

Mandarinka [93]

Answer:

$\large{\textbf{The two numbers are: 26 and 49}.\\}$

Step-by-step explanation:

$\large{\textup{assume the two numbers are $x$ and $y$.}}\\\large{\textup{The given sentences are written in mathematical terms as follows:}\\$$ x + y = 75 \hspace{25mm} (1)$$ $$ y = 2x - 3 \hspace{25mm} (2) $$ \\\textup{Substituting $(2)$ in $(1)$,}\\\begin{align*} & \implies x + 2x - 3 = 75 \\& \implies 3x = 78 \\& \implies x = 26\end{align*}\textup{Substituting $x$ in $(1), \hspace{5mm} y = 49$} }$

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2 years ago

Negative 7 bigger or smaller than negative 8

dalvyx [7]

-7 is bigger than -8

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2 years ago

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How do you find the cube root

zvonat [6]

Use a calculator to find the cube root of positive or negative numbers. Given a number x, the cube root of x is a number a such that a3 = x. If x positive a will be positive, if x is negative a will be negative. Cube roots is a specialized form of our common radicals calculator.

Example Cube Roots:The 3rd root of 64, or 64 radical 3, or the cube root of 64 is written as $ \sqrt[3]{64} = 4 $.The 3rd root of -64, or -64 radical 3, or the cube root of -64 is written as $ \sqrt[3]{-64} = -4 $.The cube root of 8 is written as $ \sqrt[3]{8} = 2 $.The cube root of 10 is written as $ \sqrt[3]{10} = 2.154435 $.

The cube root of x is the same as x raised to the 1/3 power. Written as $ \sqrt[3]{x} = x^{\frac{1}{3}} $. The common definition of the cube root of a negative number is that 
(-x)1/3 = -(x1/3).[1] For example:

The cube root of -27 is written as $ \sqrt[3]{-27} = -3 $.The cube root of -8 is written as $ \sqrt[3]{-8} = -2 $.The cube root of -64 is written as $ \sqrt[3]{-64} = -4 $.

This was not copied from a website or someone else. This was from my last year report.


f -64, or -64 radical 3, or the cube root of -64 is written as $ \sqrt[3]{-64} = -4 $.The cube root of 8 is written as $ \sqrt[3]{8} = 2 $.The cube root of 10 is written as $ \sqrt[3]{10} = 2.154435 $.

The cube root of -27 is written as $ \sqrt[3]{-27} = -3 $.The cube root of -8 is written as $ \sqrt[3]{-8} = -2 $.The cube root of -64 is written as $ \sqrt[3]{-64} = -4 $.

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3 years ago

Giving brainly answer quick noob

olga2289 [7]

Answer:

Step-by-step explanation:

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2 years ago

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A store selling newspapers orders only n = 4 of a certain newspaper because the manager does not get many calls for that publica

umka2103 [35]

Answer:

a) The expected value is 2.680642

b) The minimun number of newspapers the manager should order is 6.

Step-by-step explanation:

a) Lets call X the demanded amount of newspapers demanded, and Y the amount of newspapers sold. Note that 4 newspapers are sold when at least four newspaper are demanded, but it can be more than that.

X is a random variable of Poisson distribution with mean $\mu = 3$ , and Y is a random variable with range {0, 1, 2, 3, 4}, with the following values

PY(k) = PX(k) = ε^(-3)*(3^k)/k! for k in {0,1,2,3}
PY(4) = 1 -PX(0) - PX(1) - PX(2) - PX (3)

we obtain:

PY(0) = ε^(-3) = 0.04978..

PY(1) = ε^(-3)*3^1/1! = 3*ε^(-3) = 0.14936

PY(2) = ε^(-3)*3^2/2! = 4.5*ε^(-3) = 0.22404

PY(3) = ε^(-3)*3^3/3! = 4.5*ε^(-3) = 0.22404

PY(4) = 1- (ε^(-3)*(1+3+4.5+4.5)) = 0.352768

E(Y) = 0*PY(0)+1*PY(1)+2*PY(2)+3*PY(3)+4*PY(4) = 0.14936 + 2*0.22404 + 3*0.22404+4*0.352768 = 2.680642

The store is expected to sell 2.680642 newspapers

b) The minimun number can be obtained by applying the cummulative distribution function of X until it reaches a value higher than 0.95. If we order that many newspapers, the probability to have a number of requests not higher than that value is more 0.95, therefore the probability to have more than that amount will be less than 0.05

we know that FX(3) = PX(0)+PX(1)+PX(2)+PX(3) = 0.04978+0.14936+0.22404+0.22404 = 0.647231

FX(4) = FX(3) + PX(4) = 0.647231+ε^(-3)*3^4/4! = 0.815262

FX(5) = 0.815262+ε^(-3)*3^5/5! = 0.91608

FX(6) = 0.91608+ε^(-3)*3^6/6! = 0.966489

So, if we ask for 6 newspapers, the probability of receiving at least 6 calls is 0.966489, and the probability to receive more calls than available newspapers will be less than 0.05.

I hope this helped you!

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3 years ago