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3 years ago

What is 5.0553 x 10^-4 in standard notation?

Chemistry

1 answer:

Talja [164]3 years ago

6 0

Answer:

0.00050553

Explanation:

when the power of ten is negative, move the decimal to the left

hope this helped!

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4) What is the order of the energy pyramid.?

bazaltina [42]

Each step of the food chain in the energy pyramid is called a trophic level. Plants or other photosynthetic organisms (autotrophs) are found on the first trophic level, at the bottom of the pyramid. The next level will be the herbivores, and then the carnivores that eat the herbivores.

4 0

3 years ago

The value of Ka for phenol (a weak acid), C6H5OH, is 1.00×10-10. Write the equation for the reaction that goes with this equilib

I am Lyosha [343]

Answer:

$Ka=\frac{[C_6H_5O^-][H^+]}{[C_6H_5OH]}$

Explanation:

Hello,

In this case, weak acids are characterized by the fact they do not dissociate completely, it means they do not divide into the conjugated base and acid at all, a percent only, which is quantified via equilibrium. In such a way, the chemical equation representing such incomplete dissociation is said to be:

$C_6H_5OH\rightleftharpoons C_6H_5O^-+H^+$

Thus, we can write the law of mass action, which consider the equilibrium concentrations of all the involved species, which is also known as the acid dissociation constant which accounts for the capacity the acid has to yield hydronium ions:

$K=Ka=\frac{[C_6H_5O^-][H^+]}{[C_6H_5OH]}$

Best regards.

3 0

3 years ago

Vanillin (used to flavor vanilla ice cream and other foods) is the substance whose aroma the human nose detects in the smallest

balu736 [363]

Answer:

Cost to supply enough vanillin is $3.2\$$

Explanation:

Threshold limit of vanillin in air is $2.0\times 10^{-11}g$ per litre means there should be $2.0\times 10^{-11}g$ of vanillin in 1L of air to detect aroma of vanillin.

$1ft^{3}=28.32L$

So, $5.0\times 10^{7}ft^{3}=(5.0\times 10^{7}\times 28.32)L$

So amount of vanillin should be present to detect = $(2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32)g$

As cost of 50 g vanillin is $112\$$ therefore cost of $(2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32)g$ vanillin = $(2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32\times 112)\$ = 3.2\$$

5 0

3 years ago

An isopropyl solution contains 70 ml of isopropyl alcohol in 1.8 L of water. What is the percent by volume of the alcohol

xenn [34]

Answer:

3.74%

Explanation:

We express a solution's volume by volume percent concentration, % v/v,

Take the ratio of the isopropyl alcohol (IPA) volume to the total volume of the solution, which is 1800 mL of water+ 70 mL of IPA,

and multiply by 100 to get the percentage: 70/(1800+70) *100 = 0.0374*100 = 3.74%

5 0

3 years ago

4. Balance the following chemical equation. Say what the coefficients "a"

lisabon 2012 [21]

Answer:

a = 4

b = 3

Explanation:

SOLUTION :-

Balance it by using 'hit & trial' method , and you'll get the answer :-

2Fe₂O + 3C → 4Fe + 3CO₂

⇒ a = 4 ; b = 3

VERIFICATION :-

In reactant side of equation :-

Number of atoms in Fe = 2×2 = 4
Number of atoms in O = 2×3 = 6
Number of atoms in C = 3×1 = 3

In product side of equation :-

Number of atoms in Fe = 4×1 = 4
Number of atoms in C = 3×1 = 3
Number of atoms in O = 3×2 = 6

Number of atoms of each element is equal in both reactant & product side of equation. Hence , the equation is balanced.

6 0

3 years ago