The O₂ and the CO₂ gas exchange occurs in alveoli. the oxygen gas moves from the lungs and at same time carbon dioxide passe the the lungs from the blood and the gas exchange occurs.
The oxygen gas moves from the lungs and at same time carbon dioxide passe the the lungs from the blood and gas exchange between the alveoli and the tiny blood vessels occurs. the tiny blood vessels are called as the capillaries. the capillaries are located at the alveoli walls. every person has the hundred of millions of the alveoli present in their lungs.
Thus, in the alveoli the exchange of the oxygen gas and the carbon dioxide gas will occurs.
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NaOH+ HCl--> NaCl+ H2O
From this balanced equation, we know that 1 mol NaOH= 1 mol HCl (keep in mind this because it will be used later).
We also know that 0.15 M HCl aqueous solution (soln)= 0.15 mol HCl/ 1 L of HCl soln (this one is based on the definition of molarity).
First, we should find the mole of HCl:
16.0 mL HCl soln* (1 L HCl soln/ 1,000 mL soln)* (0.15 mol HCl/ 1L HCl soln)= 2.40* 10^(-3) mol HCl.
Now, let's find the concentration of NaOH aqueous soln:
2.40* 10^(-3) mol HCl* (1 mol NaOH/ 1 mol HCl)* (1/ 12.0 mL NaOH soln)* (1,000 mL NaOH soln/ 1L NaOH soln)= 0.20 M NaOH aqueous soln.
The final answer is (2) 0.20 M NaOH (aq).
Also, this problem can also be done by using dimensional analysis. Don't forget significant figures.
Hope this would help~
Reduction. KMnO4 is an oxidizing agent(oxidizes substances) Therefore it is reduced. The MnO4-(purple colour) from the KMnO4 is reduced to Mn2+(pale pink/ colourless).