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Blizzard [7]
3 years ago
11

what scientist design an experiment that enabled the first successful detection of an individual particle

Chemistry
1 answer:
Savatey [412]3 years ago
4 0
The appropriate response would be British physicist, Sir Joseph John Thomson OM PRS. He was an English physicist and Nobel Laureate in Physics, credited with the disclosure and known of the electron; and with the revelation of the main subatomic particle.
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Q.1 What is one joule work ? ​
Irina-Kira [14]

Answer:

See below.

Explanation:

It is equal to the energy transferred to (or work done on) an object when a force of one newton acts on that object in the direction of the force's.

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8 0
3 years ago
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Please help....... what should I do in order to study effectively?​
Maurinko [17]
1) Find a good studying spot.
2) Stay Away From Your Phone or any other things that distract you.
3) Take a break after about 1-1 hour 30 minutes- break should be about 10 minutes.
4) make sure notes are complete for what you are revising for.
5) watch videos/ use class notes/ your own notes/ revision guides.
6) test yourself by answering exam style questions or by flash cards.
7 0
3 years ago
The element chlorine has two stable isotopes, chlorine-35 with a mass of 34.97 amu and chlorine-37 with a mass of 36.95 amu. Fro
sergejj [24]

<u>Answer: </u>One isotope has a percentage abundance of 75.75 % and the percentage abundance of another isotope is 24.24%.

<u>Explanation:</u>

We are given the two stable isotopes of chlorine with their respective masses. The average atomic mass of chlorine is also given.

Average atomic mass of chlorine = 35.45 amu.

Let us assume the fractional abundance of one isotope be 'x' and the fractional abundance for another isotope will be (1 - x) because the total fractional abundance is always equal to 1.

  • For Chlorine-35 isotope:

Fractional abundance = x

Mass = 34.97 amu

  • For Chlorine-37 isotope:

Fractional abundance = 1 - x

Mass = 36.95 amu

The formula for the calculation of average atomic mass is given by:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

Putting values in above equation, we get:

35.45=34.97(x)+36.95(1-x)\\\\35.45=34.97x+36.95-36.95\\\\-1.5=-1.98x\\\\x=\frac{-1.5}{-1.98}=0.7575

1-x=1-0.7575=0.2424

Converting these two fractional abundances into percentage abundances by multiplying it with 100.

x=0.7575\times 100=75.75\%\\\\1-x=0.2424\times 100=24.24\%

Hence, one isotope has a percentage abundance of 75.75 % and the percentage abundance of another isotope is 24.24%.

7 0
3 years ago
7.0 mol Mn reacts with 5.0 mol
Elenna [48]

The moles of MnO formed with the reaction of 5 moles of Mn is 3 moles.

<h3>What is a limiting reagent?</h3><h3 />

In a chemical reaction, the reagent that is present in a lesser quantity and governs the rate of the reaction is termed as the limiting reagent.

In the reaction of the formation of MnO, according to the stoichiometric law 2 moles of Mn reacts with 1 moles of Oxygen.

Thus, the moles of oxygen consumed by 7 moles of Mn is:

2 moles Mn = 1 mole O₂

7 moles Mn = 3.5 moles O₂

The available moles of O₂ = 5 mol.

The remaining moles of O₂ = 5-3.5 moles

The remaining moles of O₂ = 1.5 moles

The reaction of 5 moles Mn requires 2.5 moles of O₂, whereas the available moles of oxygen is 1.5 moles. Thus, oxygen serves as the limiting reagent.

The moles of MnO formed with the reaction of 5 moles Mn and 1.5 moles O₂

1 mole O₂ = 2 moles MnO

1.5 moles O₂ = 2 * 1.5 moles MnO

1.5 moles O₂ = 3 moles MnO

Thus, the moles of MnO formed with the reaction of 5 moles of Mn with the available oxygen is 3 moles.

Learn more about stoichiometric law, here:

brainly.com/question/14465605

#SPJ1

6 0
2 years ago
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Bonds between amino acids are what type of bonds?<br> covalent<br> peptide<br> hydrogen<br> ionic
Blababa [14]
Amino acids form peptide type of bonds...;

3 0
3 years ago
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