Hello!
The exercise doesn't say the final temperature, but we are going to assume that the increase is of 20 °C (The procedure is the same, just change the final temperature) To calculate the heat absorbed by water, we need to use the equation for
Heat Transfer, in the following way (assuming that the heat increase is 20°C):

So, the Heat absorbed by water is
1297,04 J
Have a nice day!
<span>H</span>₃<span>PO</span>₄<span> - Phosphoric Acid :
H</span>₃<span>PO</span>₄<span> = 1.0 * 3 + 31.0 + 16.0 * 4 = 98.0 g/mol
hope this helps!</span>
It depends on the direction of the arrow.
If the arrow goes like this ---> the reactant would be 2Fe2O3
If the arrow goes like this <--- the reactants would be 4Fe + 3O2
<u>Answer:</u> The concentration of A after 865 seconds is 0.00125 M
<u>Explanation:</u>
The integrated rate law equation for second order reaction follows:
![k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B1%7D%7Bt%7D%5Cleft%20%28%5Cfrac%7B1%7D%7B%5BA%5D%7D-%5Cfrac%7B1%7D%7B%5BA%5D_o%7D%5Cright%29)
where,
k = rate constant = 
t = time taken = 865 second
[A] = concentration of substance after time 't' = ?
= Initial concentration = 0.00440 M
Putting values in above equation, we get:
![0.660=\frac{1}{865}\left (\frac{1}{[A]}-\frac{1}{(0.00440)}\right)](https://tex.z-dn.net/?f=0.660%3D%5Cfrac%7B1%7D%7B865%7D%5Cleft%20%28%5Cfrac%7B1%7D%7B%5BA%5D%7D-%5Cfrac%7B1%7D%7B%280.00440%29%7D%5Cright%29)
![[A]=0.00125M](https://tex.z-dn.net/?f=%5BA%5D%3D0.00125M)
Hence, the concentration of A after 865 seconds is 0.00125 M
Answer:
Th answer is b. convection.
Explanation:
As the heat rises it cools down and it sinks and as the cold sinks it heats up so then it rises back up.