Answer: they will meet and make a biger wave then seperat
Explanation: When two or more waves meet, they interact with each other. The interaction of waves with other waves is called wave interference. Wave interference may occur when two waves that are traveling in opposite directions meet. The two waves pass through each other, and this affects their amplitude.
Answer:
Explanation:
A) False.
Glucosidase (not calnexin nor calreticulin) helps to remove glucose residue.
Both calnexin and calreticulin rather have an affinity for last glucose residue of misfolded protein (Only misfolded proteins are marked by glycosyltransferase by attaching glucose residue). They attach with misfolded protein and with the help of other proteins like ERp57 (a type of protein disulfide isomerase) and try to fold it properly. If protein is properly folded then glucosidase removes the glucose residue thereby releasing the properly folded protein from calnexin or calreticulin. and now protein is transported to the Golgi body. If folding is still not proper then the same cycle of glycosylation -binding of calnexin/calreticulin and effort to fold it properly is repeated.
B) True.
Transketolase is a key enzyme of the pentose phosphate pathway. It contains thiamine diphosphate (TPP) as a cofactor. it does transfer 2 carbon residue from a ketose to aldose. So, effectively it converts one ketose sugar to aldose with 2 carbonless and aldose to ketose with 2 carbon more.
C) True.
Theoretically, for the evolution of one molecule of oxygen, only 8 photons are required. But in practice, it is known that there are many variants like wavelength and the energy of the photon. The larger the wavelength, like the one which is used in PS1 (more than 700nM), the lesser the energy. Secondly, the energy of the photon is also wasted as heat energy. Because of these factors, more than 8 photons are needed in reality.
D) Wrong.
Fructose 2,6 bisphosphate is a key substrate and affects both the enzymes- phosphofructokinase and fructose bisphosphatase allosterically during gluconeogenesis. It strongly favors the breakdown of glucose during glycolysis by activating phosphofructokinase but it inhibits fructose bisphosphatase. Hence it activates the kinase enzyme while inhibiting the phosphatase and maintains a huge supply of glucose in the system.
E) Wrong.
The Calvin cycle shares similarity with the pentose phosphate pathway as both are involved in the synthesis of sugar (Triose and Ribose). However, it does not share similarity with enzymes of glycolysis (which is primarily focused on the breakdown of glucose) and gluconeogenesis.
Answer:
So there is83.6g CO2 produced
Explanation:
Burning carbon with air has the following equation
C + O2 → CO2
For 1 mol Carbon, we have 1 mol O2 and 1 mol CO2
Step 2: Calculating moles
mole C = 22.8g / 12g/mole
Mole C = 1.9 mole
1.9 mole C will completely react
Since for each mole C there is 1 mole O2 and 1 mole CO2
This means there will also react 1.9 mole of 02, to be formed 1.9 mole of CO2
mole CO2 = mass CO2 / Molar mass CO2
mass CO2 = 1.9 mole CO2 * 44g/mole =<u>83.6g CO2</u>
In this reaction 18.2 g of O2 remained unreacted
we can control this: 79g - 18.2 g = 60.8g
1.9 mole * 32g/mol = 60.8g
So there is83.6g CO2 produced
It is an element. Aluminun foil is aluminum prepared in thin leaves.
