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Lena [83]
2 years ago
13

How many grams in 4.53 moles of MgBr2

Chemistry
1 answer:
musickatia [10]2 years ago
8 0

Answer:

520.12554

Explanation:

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The concentration in molality of hcl in a solution that is prepared by dissolving 5.5 g of hcl in 200.0 g of c2h6o is __________
PIT_PIT [208]

Molality is one way of expressing concentration of a solute in a solution. It is expressed as the mole of solute per kilogram of the solvent. To calculate for the molality of the given solution, we need to convert the mass of solute into moles and divide it to the mass of the solvent.

<span>
Moles of HCl = 5.5 g HCl ( 1 mol HCl / 36.46 g HCl ) = 0.1509 mol HCl</span>

<span>
Molality = 0.1509 mol HCl / 200 g C2H6O ( 1 kg / 1000 g )
Molality = 0.7543 mol / kg</span>


<span>The concentration in molality of hcl in a solution that is prepared by dissolving 5.5 g of hcl in 200.0 g of c2h6o is 0.7453 molal.</span>
6 0
2 years ago
How many of each component are shown in the diagram? Check all that apply. one battery two switches two batteries two resistors
VikaD [51]
<h3>In reference to the diagram attached </h3><h3>Answer:</h3>

one battery, two switches, and three light bulbs

Explanation:

  • A circuit is an arrangement that shows the flow of electrons from a current source such as a battery.
  • The diagram shows a circuit that contains one battery, two switches, and three light bulbs.
  • The switches serves to close the circuit when necessary.
  • The battery supplies current to the circuit.
  • The light bulbs are used for lighting.

8 0
3 years ago
Read 2 more answers
Which element would most likely be a shiny solid at room temperature and a good conductor of electricity?
Alborosie

Answer:

A

Explanation:

rest are nonmetals and they are not shiny

7 0
2 years ago
 
Mashutka [201]

sodium cloride is salt created from sodium Na and chlorine Ci

Na-sodium Ca- calcium

Ci-chlorine FL- flerovium

Ca- calcium Br-bromine

H- hydrogen He-helium

6 0
3 years ago
Read 2 more answers
How many molecules are in 0.55 moles of Cu(NO3)2?
xeze [42]
<h3>Answer:</h3>

3.3 × 10²³ molecules Cu(NO₃)₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

0.55 mol Cu(NO₃)₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                     \displaystyle 0.55 \ mol \ Cu(NO_3)_2(\frac{6.022 \cdot 10^{23} \ molecules \ Cu(NO_3)_2}{1 \ mol \ Cu(NO_3)_2})
  2. [DA] Multiply/Divide [Cancel out units]:                                                         \displaystyle 3.3121 \cdot 10^{23} \ molecules \ Cu(NO_3)_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

3.3121 × 10²³ molecules Cu(NO₃)₂ ≈ 3.3 × 10²³ molecules Cu(NO₃)₂

4 0
3 years ago
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