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2 years ago

Fractions from 6 to 7, with an interval of between each pair of fractions

Mathematics

1 answer:

EastWind [94]2 years ago

3 0

Answer:

6.7

Step-by-step explanation:

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A town has a population of 5000 and grows at 4% every year. What will be the population after 7 years, to the nearest whole numb

Rudiy27

I think this is.. ↓

grows 4% at every year

after 7 years ↓↓

4 × 7 = 28

A town has a population of 5000

28% of 5000 = 1400

5000 + 1400 = 6400

after 7 years, town has 6400 population = after 7 year grows 28%

7 0

2 years ago

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Obtain the general solution to the equation. (x^2+10) + xy = 4x=0 The general solution is y(x) = ignoring lost solutions, if any

alukav5142 [94]

Answer:

$y(x)=4+\frac{C}{\sqrt{x^2+10}}$

Step-by-step explanation:

We are given that a differential equation

$(x^2+10)y'+xy-4x=0$

We have to find the general solution of given differential equation

$y'+\frac{x}{x^2+10}y-\frac{4x}{x^2+10}=0$

$y'+\frac{x}{x^2+10}y=4\frac{x}{x^2+10}$

Compare with

$y'+P(x) y=Q(x)$

We get

$P(x)=\frac{x}{x^2+10}$

$Q(x)=\frac{4x}{x^2+10}$

I.F= $e^{\int\frac{x}{x^2+10} dx}=e^{\frac{1}{2}ln(x^2+10)}$

$e^{ln\sqrt(x^2+10)}=\sqrt{x^2+10}$

$y\cdot \sqrt{x^2+10}=\int \frac{4x}{x^2+10}\times \sqrt{x^2+10} dx+C$

$y\cdot \sqrt{x^2+10}=\int \frac{4x}{\sqrt{x^2+10}}+C$

$y\cdot \sqrt{x^2+10}=4\sqrt{x^2+10}+C$

$y(x)=4+\frac{C}{\sqrt{x^2+10}}$

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2 years ago

Write an equation to represent each graph

givi [52]

equation for first figure=2x+y=2

equation for second figure= 4x-y=8

(use formula x/a+y/b=1)

where, a=x component and b= y component..

7 0

2 years ago

Pls help it’s due today

seraphim [82]

Answer:

ion know

Step-by-step explanation:

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2 years ago

Csc A - sin A = <br><br> A. (cos^2A) / (sinA)<br> B. (1 - sinA) / (sinA) <br> C. (1 - sinA) / (cosA)

julsineya [31]

Answer:

A) $\frac{cos^2A}{sinA}$

Step-by-step explanation:

$cscA-sinA\\\\\frac{1}{sinA}-sinA\\ \\\frac{1}{sinA}-\frac{sin^2A}{sinA}\\ \\ \frac{1-sin^2A}{sinA}\\ \\\frac{cos^2A}{sinA}$

4 0

2 years ago

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