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3 years ago

Use this balanced equation to help you solve:

Chemistry

1 answer:

valentina_108 [34]3 years ago

5 0

1. 842g of NaOH will form 547.3 g of Al(OH)₃

2. The yield is 93.55%

<u>Explanation:</u>

3NaOH + Al → Al(OH)₃ + 3Na

Molar mass of NaOH = 40 g/mol

Molar mass of Al = 27 g/mol

Molar mass of Al(OH)₃ = 78 g/mol

According to the balanced equation:

3 moles of NaOH requires 1 mole of Al to form 1 mole of Al(OH)₃

The ratio of NaOH : Al : Al(OH)₃ = 3 : 1 : 1

3 X 40 g of NaOH reacts with 27 g of Al to form 78 g of Al(OH)₃

120 g of NaOH + 27g of Al → 78 g of Al(OH)₃

120g of NaOH form 78g of Al(OH)₃

1g of NaOH will form $\frac{78}{120}$ g of Al(OH)₃

842g of NaOH will form $\frac{78}{120} X 842 g$ of Al(OH)₃

= 547.3 g of Al(OH)₃

Therefore, 842g of NaOH will form 547.3 g of Al(OH)₃

2. Only 512 g of Al(OH)₃ is formed

Yield % = ?

$Yield = \frac{512}{547.3} X 100\\\\Yield = 93.55$

Therefore, the yield is 93.55%

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