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bagirrra123 [75]
3 years ago
5

Which of the following points lies on the graph of this equation? y = 2x – 2 Select one: a. (-1, -1) b. (1, 0) c. (1, 4) d. (-1,

-2)
Mathematics
1 answer:
Ket [755]3 years ago
7 0
For this case we have the following equation:
 y = 2x - 2
 For the point (1, 0) we have:
 x = 1
 y = 0
 Substituting values we have:
 0 = 2 (1) - 2
 0 = 2 - 2
 0 = 0
 We observe that equality is fulfilled and therefore, the point belongs to the equation.
 Answer:
 b. (1, 0)
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A circle is placed in a square with a side length of 18 mm, as shown below. Find the area of the shaded region.
finlep [7]
Answer: the shaded region = 69.66mm^2

Explanation:
Assume shaded region is X
Then :
X + Area of circle = area of square
X = area of square - area of circle

Find area of square:
Side length = 18mm
Area = 18 x 18 = 324

Find area of circle:
Side length of a square = the diameter of the circle = 18mm
And r(radius) = d/2 = 18/2 = 9
Area = pi x 9^2 = 254.34

Now find X
X = 324 - 254.34 = 69.66
3 0
3 years ago
Suppose cos(x)= -1/3, where π/2 ≤ x ≤ π. What is the value of tan(2x). EDGE
AVprozaik [17]

Answer:

D

Step-by-step explanation:

We are given that:

\displaystyle \cos x = -\frac{1}{3}\text{ where } \pi /2 \leq x \leq \pi

And we want to find the value of tan(2<em>x</em>).

Note that since <em>x</em> is between π/2 and π, it is in QII.

In QII, cosine and tangent are negative and only sine is positive.

We can rewrite our expression as:

\displaystyle \tan(2x)=\frac{\sin(2x)}{\cos(2x)}

Using double angle identities:

\displaystyle  \tan(2x)=\frac{2\sin x\cos x}{\cos^2 x-\sin^2 x}

Since cosine relates the ratio of the adjacent side to the hypotenuse and we are given that cos(<em>x</em>) = -1/3, this means that our adjacent side is one and our hypotenuse is three (we can ignore the negative). Using this information, find the opposite side:

\displaystyle o=\sqrt{3^2-1^2}=\sqrt{8}=2\sqrt{2}

So, our adjacent side is 1, our opposite side is 2√2, and our hypotenuse is 3.

From the above information, substitute in appropriate values. And since <em>x</em> is in QII, cosine and tangent will be negative while sine will be positive. Hence:

<h2>\displaystyle  \tan(2x)=\frac{2(2\sqrt{2}/3)(-1/3)}{(-1/3)^2-(2\sqrt{2}/3)^2}</h2>

Simplify:

\displaystyle  \tan(2x)=\frac{-4\sqrt{2}/9}{(1/9)-(8/9)}

Evaluate:

\displaystyle  \tan(2x)=\frac{-4\sqrt{2}/9}{-7/9} = \frac{4\sqrt{2}}{7}

The final answer is positive, so we can eliminate A and B.

We can simplify D to:

\displaystyle \frac{2\sqrt{8}}{7}=\frac{2(2\sqrt{2}}{7}=\frac{4\sqrt{2}}{7}

So, our answer is D.

7 0
3 years ago
Polygon ABCD will be dilated by a scale factor of 2.2 with the origin as the center of dilation, resulting in the image A'B'C'D'
ikadub [295]
The answer is A. <span>m = undefined, C'D' = 13.2 units. When you dilate both C and D with the scale factor 2.2 with the origin as the center of dilation, their coordinates respectively become the following:
C' (22, 13.2) and D (22,26.4)

The difference between 26.4 and 13.2 is 13.2. The slope is undefined since it is s vertical line.

</span>
4 0
3 years ago
Read 2 more answers
What is 5 medium apples divided by 475 calories?
Arturiano [62]
Your answer would be 95 calories per apple
6 0
3 years ago
Is a rise of -7 the same as a fall of 7
iVinArrow [24]

The rise of -7 means that there is 7 less. The fall of 7 would mean that it is also 7 less. So, yes. They are both the same thing.

7 0
3 years ago
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