Answer:
14 g of N2
Explanation:
If we look at the options, we will notice that the correct answer needs to be a gas that has about half of the molecular mass of the gas.
If we consider nitrogen gas whose molecular mass is 28g/mol, half of the molecular mass is 14 g.
So;
28g of N2 contains 6.02 × 10^23 molecules of N2
14g of N2 contains 14 × 6.02 × 10^23 /28
= 3.0 x 10^23
D= mass over volume
So, density equals 9.0g divided by 45ml.
SO, D=.25 g/ml
I'm not 100% sure this is correct, though. Best if luck. ♡
Answer:
v2= 5.404L
Explanation:
using Boyle's law
p1 x v1 = p2 x v2
101.325 x 4.31 = 80.8 x v2
v2= (101.325 x 4.31)\80.8
v2= 5.404L
Electron domain geometry takes into account the bonds and the free electrons around the atom to predict the geometry.
A tigonal planar geometry means that all the electron domains are in the plane and that they are as far away as they can. That means that there are three electron domains in the plane separated at 120 ° each other.
sp2 means that there are three hybrid electron domains, and the geometrh that leads to the minimal repulsion force is they placed at 120°, which exactly the trigonal planar geometry described up.
Then the answer is sp2
You can check in your book, that sp corresponds to two domains, located linearly, at 180°; and sp3 is four domains with the form of tetrahedral with 109.5° angles.
Answer is: 0.5 dm³ to dissolve.
m(CuSO₄) = 11.2 g.
c(CuSO₄) = 0.140 mol/dm³,
V(CuSO₄) = ?
n(CuSO₄) = m(CuSO₄) ÷ M(CuSO₄).
n(CuSO₄) = 11.2 g ÷ 159.6 g/mol.
n(CuSO₄) = 0.07 mol.
V(CuSO₄) = n(CuSO₄) ÷ c(CuSO₄).
V(CuSO₄) = 0.07 mol ÷ 0.14 mol/dm³.
V(CuSO₄) = 0.5 dm³.
