Answer:
2. 2.74 L
3. 488 K
4. 7.47 L
5. 38.6 L
6. 2.85 mol
7. 319 K
8. 3.43 kPa
Explanation:
Generally speaking, you want to convert units to SI units, but in this case, we are working with ratios. This makes up for using the units that wouldn't appropriate elsewhere.
2. Use the equation P₁V₁ = P₂V₂. Solve for V₂.
(3.05 L)(870 kPa) = (969 kPa)(V₂)
V₂ = 2.74 L.
3. Use the equation V₁/T₁ = V₂/T₂. Solve for T₂.
(3.32 L)/(360 K) = (4.50 L)/(T₂)
T₂ = 488 K.
4. Do the same as above, but for V₂.
(5.10 L)/(-56°C) = V₂/(-82°C)
V₂ = 7.47 L
5. Use the equation V₁/n₁ = V₂/n₂. Solve for V₂.
(37.2 L)/(0.750 mol) = (V₂)/(0.778 mol)
V₂ = 38.6 L
6. Do the same as above, but for n₂.
(86.0 L)/(2.65 mol) = (92.5 L)(n₂)
n₂ = 2.85 mol
7. Use the equation P₁/T₁ = P₂/T₂. Solve for T₂.
(3.00 atm)/(390 K) = (2.45 atm)/(T₂)
T₂ = 319 K
8. Do the same as above, but for P₂.
In this specific case, however you will need to convert units. Since both temperatures don't have the same sign, the ratio won't come out right. Convert to Kelvin. Add 273.15 to the temperature in Celsius to convert to Kelvin -12.3°C = 260.85 K 25°C = 298.15 K.
(3.00 kPa)/(260.85 K) = P₂/(298.15 K)
P₂ = 3.43 kPa
There is a lot in here... If you are confused about something, let me know!
= 0.267 mol C₈H₁₈
