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4 years ago

Describe the patterns created by minerals in foliated rock.

1 answer:

3 0

Foliated Metamorphic Rocks. Foliated metamorphic rocks are formed within the Earth's interior under extremely high pressures that are unequal, occurring when the pressure is greater in one direction than in the others (directed pressure). ... This reduces the overall pressure on the rock and gives it a stripped look.

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Suppose a 65 kg person stands at the edge of a 6.5 m diameter merry-go-round turntable that is mounted on frictionless bearings

Hatshy [7]

Answer:0.316 rad/s

Explanation:

Given

mass of Person $m=65 kg$

velocity of person $v=3.8 m/s$

diameter of turntable $d=6.5 m$

moment of Inertia of the table $I_0=1850 kg-m^2$

Moment of inertia of Person I

$I=mr^2=65\times (\frac{6.5}{2})^2$

$I=686.56 kg-m^2$

initial angular velocity $\omega _1=\frac{v}{r}$

$\omega _1=\frac{3.8}{3.25}=1.17 rad/s$

Conserving Angular momentum

$I\omega _1=(I+I_0)\omega _2$ , where $\omega _2=final\ angular\ velocity$

$686.56\times 1.17=(686.56+1850)\times \omega _2$

$\omega _2=\frac{686.56}{2536.56}\times 1.17$

$\omega _2=0.316 rad/s$

4 0

3 years ago

oxygen (o) is a gas found in the 16th column of the periodic table. What statement is true about oxygen and he other elements in

Tpy6a [65]

<h3>I'm pretty sure, all the elements in the column have similar chemical properties.</h3>

8 0

4 years ago

1. How is electric potential energy similar to gravitational potential energy? How is it different? Where will an electron bound

Korolek [52]

Both ve similar equations
<span>both are energies of one object w.r.t another </span>
<span>differences- electric pe is due to electrostatic force and gravitational pe is due to gravitational force </span>
<span>electric pe is > than gravitational pe since electrostatic force> gravitational force </span>
<span>electron bound in an atom ll ve largest potential enegy in its ground state. i think hope it helps</span>

7 0

3 years ago

A 200 kg weather rocket is loaded with 100 kg of fuel and fired straight up. It accelerates upward at 35 m/s2 for 35 s , then ru

r-ruslan [8.4K]

Answer:

T = 295.57 s

Explanation:

given,

mass of the rocket = 200 Kg

mass of the fuel = 100 Kg

acceleration = 35 m/s²

time, t = 35 s

time taken by the rocket to hit the ground, = ?

Final speed of the rocket when fuel is empty

using equation of motion

v = u + a t

v = 0 + 35 x 35

v = 1225 m/s

height of the rocket where fuel is empty

v² = u² + 2 a s

1225² = 0 + 2 x 35 x h₁

h₁ = 21437.5 m

After 35 s the rocket will be moving upward till the final velocity becomes zero.

Now, using equation of motion to find the height after 35 s

v² = u² + 2 g h₂

0² = 1225² + 2 x (-9.8) h₂

h₂ = 76562.5 m

total height = h₁ + h₂

= 76562.5 m + 21437.5 m = 98000 m

now, time taken by before the rocket hit the ground

using equation of motion

$s = u t +\dfrac{1}{2}at^2$

$-13500 = 1225 t -\dfrac{1}{2}\times 9.8 \times t^2$

negative sign is used because the distance travel by the rocket is downward.

4.9 t² - 1225 t - 13500 = 0

$t = \dfrac{-(-1225)\pm \sqrt{1225^2 - 4\times 4.9 \times (-13500)}}{2\times 4.9}$

t = 260.57 s

neglecting the negative sign

total time the rocket was in air

T = t₁ + t₂

T = 35 + 260.57

T = 295.57 s

Time for which rocket was in air is equal to 295.57 s.

6 0

3 years ago

Imagine that you are driving up a mountain on a very curvy road at night when the air is very still and not moving. The air temp

timama [110]

Answer:

Diathermy and atmospheric pressure

Explanation:

When the energy from the Sun comes to the Earth, it hits first the atmosphere, but the air contained is almost unaffected by it because the molecules are not tight enough to absorb its incoming energy.

Later on, the sunlight reaches the soil, thus absorbing part of the energy and reflecting the rest. Because of this reflection, the air near to the ground begins to heat through convection and as it gains height the air pressure (thus the air molecules begin to separate more from each other) decreases and the energy transfer to them is more difficult. As a result, as you gain height, the air temperature decreases at a rate of 6.8 ºC every 1,000 meters.

8 0

3 years ago