Answer:
- the speed of a person "stuck" to the wall is 14.8 m/s
- the normal force of the wall on a rider of m=54kg is 1851 N
- the minimum coefficient of friction needed between the wall and the person is 0.29
Explanation:
Given information:
the radius of the cylindrical room, R = 6.4 m
the room spin with frequency, ω = 22.1 rev/minutes = 22.1 = 2.31 rad/s
mass of rider, m = 54 kg
the speed of a person "stuck" to the wall
v = ω R
= 2.31 x 6.4
= 14.8 m/s
the normal force of the wall on a rider
F = m a
a = ω^2 R
= R
=
F =
=
= 1851 N
the minimum coefficient of friction needed between the wall and the person
F(friction) = μ N
W = μ N
m g = μ
g = μ
μ =
=
= 0.29