3 years ago

A baseball pitcher throws a 0.14 kg ball toward a batter who is 18 m away.

Physics

1 answer:

Olin [163]3 years ago

5 0

Answer:

A. 112 J

Explanation:

KE = ½mv² = ½(0.14)40² = 112 J

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The answer would be B the temperature of the juice was the temperature of the surrounding air

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A car is traveling at a speed of 38.0 m/s on an interstate highway where the speed limit is 75.0 mi/h. Is the driver exceeding t

Tom [10]

Answer: Yes, he is exceeding the speed limit

Explanation:

Hi!

This is problem about unit conversion

1 mile = 1,609.344 m

Then the speed limit v is:

v = 75 mi/h = 120,700.8 m/h

1 hour = 60 min = 60*60 s = 3,600 s

v = (120,700.8/3,600) m/s = 33.52 m/s

38 m/s is higher than the speed limit v.

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3 years ago

In this first example of constant accelerated motion, we will simply consider a car that is initially traveling along a straight

algol13

Answer:

$v_{f} =25m/s$

Explanation:

Kinematics equation for constant acceleration:

$v_{f} =v_{o} + at=15+2*5=25m/s$

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3 years ago

Given two vectors A=4i^+3j^ and vector B=5i^-2j^.find the magnitude of each vector

Flura [38]

Answer:

Magnitude of A=5

Magnitude of B=5.39

Explanation:

The magnitude of Vectors in Rectangular Form

Given a vector v in its rectangular form:

$\mathbf{v}=x\hat i+y\hat j$

The magnitude of v is:

$\mid\mid\mathbf{v}\mid \mid=\sqrt{x^2+y^2}$

We are given the vectors

$\mathbf{A}=4\hat i+3\hat j$

$\mathbf{B}=5\hat i-2\hat j$

Their magnitudes are:

$\mid\mid\mathbf{A}\mid \mid=\sqrt{4^2+3^2}=\sqrt{16+9}=\sqrt{25}$

$\mid\mid\mathbf{A}\mid \mid=5$

$\mid\mid\mathbf{B}\mid \mid=\sqrt{5^2+(-2)^2}=\sqrt{25+4}=\sqrt{29}$

$\mid\mid\mathbf{B}\mid \mid=\sqrt{29}=5.39$

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3 years ago