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3 years ago

How long must a current of 100mA flow so as to transfer a charge of 80 C?

Physics

2 answers:

bulgar [2K]3 years ago

8 0

Answer:

800 secs

Explanation:

Q = it

80 = 100 x10^-3 t

t = 80/0.1

= 800secs

defon3 years ago

6 0

Answer:

800s

Explanation:

Q=It

where,

Q=80c

I =100MA=0.1A

t=?

Q=It

800=0.1×t

t=80×0.1

t=800s

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A 180 meter long train, travelling at a constant speed, is passing a car driving on an adjacent lane at a speed of 72 km/h. Know

Lana71 [14]

Answer:

The velocity of the train is 82.8 km/h

Explanation:

The equation for the position of the train and the car is as follows:

x = x0 + v · t

Where:

x = position at time "t".

x0 = initial position.

v = velocity.

t = time.

First, let´s calculate the distance traveled by the car in 60 s (1/60 h). Let´s place the origin of the frame of reference at the front of the train when it starts to pass the car so that the initial position of the car is 0 (x0 = 0 m):

x = 0 m + 72 km/h · (1/60) h

x = 1.2 km.

Then, if the whole train passes the car at that time, the position of the front of the train at that time will be 1.2 km + 0.18 km = 1.38 km.

Then using the equation of position we can obtain the velocity:

x = x0 + v · t

1.38 km = 0 m + v · (1/60) h

1.38 km / (1/60) h = v

v = 82.8 km/h

The velocity of the train is 82,8 km/h

The same result could be obtained using the rear of the train. You only have to identify where the rear is at t = 0 and where it is at t = 60 s.

Try it!

6 0

3 years ago

A group of 25 particles have the following speeds:

svp [43]

Answer:

Part a: The average speed is 24.12 m/s

Part b: The rms speed is 25.55 m/s

Part c: The most probable speed is 17 m/s.

Explanation:

Part a

Average Speed

<em>Average speed is given as </em>

<em /> $v_{avg}=\frac{\sum}{n}$

$v_{avg}=\frac{(2 \times 11) +(7 \times 17)+(4 \times 19)+(3 \times 27) +(6 \times 32) +(1 \times 33)+(2 \times 40) }{25}\\v_{avg}=\frac{22+119+76+81+192+33+80}{25}\\v_{avg}=\frac{603}{25}\\v_{avg}=24.12 m/s$

So the average speed is 24.12 m/s

Part b

RMS Speed

$v_{rms}=\frac{\sum v^2}{n}$

$v_{rms}=\sqrt{\frac{(2 \times 11^2) +(7 \times 17^2)+(4 \times 19^2)+(3 \times 27^2) +(6 \times 32^2) +(1 \times 33^2)+(2 \times 40^2) }{25}} \\v_{rms}=\sqrt{\frac{242+2023+1444+2187+6144+1089+3200}{25}}\\\\v_{rms}=\sqrt{\frac{16329}{25}}\\v_{rms}=\sqrt{653.16}\\v_{rms}=25.55 m/s$

So the rms speed is 25.55 m/s

Part c

Most Probable Speed

As 7 particles have speed of 17 m/s i.e. 7 is the highest frequency so 17 m/s is the most probable speed.

3 0

3 years ago

Monochromatic light is incident on two slits separated by 0,2 mm. An interference pattern is observed on a screen 3,7 m away. Th

zalisa [80]

Answer:

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Explanation:

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$y_m=\frac{m\lambda D}{d}$ (1)

ym: position of a bright fringe

D: distance from the slits to the screen = 3,7 m

d: distance between slits = 0,2mm = 0,2 *10^-3 m

m: order of the fringe

λ: wavelength of the light

You have the distance from the central peak to the third fringe (0,048m). Then, you can use the equation (1) with m=3 and solve for the wavelength:

$y_3=\frac{3\lambda D}{d}\\\\\lambda=\frac{dy_3}{3D}=\frac{(0,2*10^{-3}m)(0,048m)}{3(3,7m)}=8,64*10^{-7}m\\\\\lambda=864*10^{-9}m=864nm$

henc, the wavelength of the light is 864nm

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maw [93]

Answer:

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3 years ago

How long must a current of 100mA flow so as to transfer a charge of 80 C? ​

How long must a current of 100mA flow so as to transfer a charge of 80 C?