Let L and S represent the weights of large and small boxes, respectively. The problem statement gives rise to two equations:
.. 7L +9S = 273
.. 5L +3S = 141
You can solve these equations various ways. Using "elimination", we can multiply the second equation by 3 and subtract the first equation.
.. 3(5L +3S) -(7L +9S) = 3(141) -(273)
.. 8L = 150
.. L = 150/8 = 18.75
Then we can substitute into either equation to find S. Let's use the second one.
.. 5*18.75 +3S = 141
.. S = (141 -93.75)/3 = 15.75
A large box weighs 18.75 kg; a small box weighs 15.75 kg.
In order to find the second endpoint or a line segment given the first and the midpoint, you need to realize that the midpoint is an average of the two endpoints. Given that fact, we can derive this formula looking at x values of points A and B with midpoint M. Remember this is only looking at the x values.
(A + B)/2 = M
So if we are looking for A, we can solve for A and use this modified formula.
(A + B)/2 = M
A + B = 2M
A = 2M - B
Now we can do this with the y values of these points as well. We then have the coordinates of both parts of A.
Answer:(x-1)(x+8)
Step-by-step explanation: You need to set it up as (x+y)(x+z) format. To get that you need to flip the zeroes making them the opposite. So the answer in this case would be (x-1)(x+8).
5in : 200mi
7in : xmi
One inch represents 40 miles.
7 * 40 miles = 280 miles.
The two cities are 280 miles apart.
Answer:
19°
Step-by-step explanation:
Set up the equation (triangles add up to 180 degrees)(Right angles are 90 degrees).
39 + 90 + 2x + 13 = 180
142 + 2x = 180
2x = 38
x = 19
