Answer:
A. 6
B. 3 and 3
Step-by-step explanation:
A) 8x3/4
B) since the area is three and you have to spit the triangle down the middle...
You draw a line diagonally from the top right corner to the bottom left corner and the area would be 3 and 3 because 6 in half is 3
Answer:
28
Step-by-step explanation:
D = 109 - 84 = 134 - 109 = 25
2nd term = 34 + 25 = 59
<u>Answer</u>
c. buying it at a 10 percent discount without sales tax.
<u>Explanation</u>
We are going to compare the 3 choices and then determine the most cost effective.
<em>a. using a paid membership card to buy it at a 10 percent discount.</em>
10% of $100 = 10/100×100 = $10
cost = $100 - $10 = $90
On top of this $90 there is the charges of the membership card.
<em> b. buying it online at a 10 percent discount with a $5 shipping charge.</em>
100%-10% = 90%
90% of 100 = $90
Cost: $90 + $5 = $95
<em>c. buying it at a 10 percent discount without sales tax.</em>
100% - 10% = 90%
90/100 × 100 = $90. This is the must cost effective method since there is no other cost involved.
Answer:
Step-by-step explanation:
Given that the demand for the 6 p.m. flight from Toledo Express Airport to Chicago's O'Hare Airport on Cheapfare Airlines is normally distributed with a mean of 132 passengers and a standard deviation of 42
Let X be the no of passengers who report
X is N(132, 42)
Or Z is ![\frac{x-132}{42}](https://tex.z-dn.net/?f=%5Cfrac%7Bx-132%7D%7B42%7D)
a) Suppose a Boeing 757 with a capacity of 183 passengers is assigned to this flight.
the probability that the demand will exceed the capacity of this airplane
=![P(X>183) = P(Z>1.21) =](https://tex.z-dn.net/?f=P%28X%3E183%29%20%3D%20P%28Z%3E1.21%29%20%3D)
![=0.5-0.3869\\=0.1131](https://tex.z-dn.net/?f=%3D0.5-0.3869%5C%5C%3D0.1131)
b) the probability that the demand for this flight will be at least 80 passengers but no more than 200 passengers
=![P(80\leq x\leq 200)\\= P(-1.23\leq z\leq 1.62)\\](https://tex.z-dn.net/?f=P%2880%5Cleq%20x%5Cleq%20200%29%5C%5C%3D%20P%28-1.23%5Cleq%20z%5Cleq%201.62%29%5C%5C)
=0.4474+0.3907
=0.8381
c) the probability that the demand for this flight will be less than 100 passengers
![=P(x](https://tex.z-dn.net/?f=%3DP%28x%3C100%29%5C%5C%3DP%28z%3C-0.76%29%5C%5C%3D0.5-0.2764%5C%5C%3D0.2236)
d) If Cheapfare Airlines wants to limit the probability that this flight is overbooked to 3%, how much capacity should the airplane that is used for this flight have? passengers
=![P(Z>c)=0.03\\c=1.88\\X=132+1.88(42)\\=210.96](https://tex.z-dn.net/?f=P%28Z%3Ec%29%3D0.03%5C%5Cc%3D1.88%5C%5CX%3D132%2B1.88%2842%29%5C%5C%3D210.96)
e) 79th percentile of this distribution
=![132+0.81(42)\\= 166.02](https://tex.z-dn.net/?f=132%2B0.81%2842%29%5C%5C%3D%20166.02)