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ivann1987 [24]
2 years ago
11

Which ordered pale is a solution to the system of equations?

Mathematics
1 answer:
Softa [21]2 years ago
5 0

Answer:

c) (-2, 1)

Step-by-step explanation:

3x - 3y = -9

2x + y = -3

2x + y = -3

-2x       -2x

y = -2x - 3

3x - 3y = -9

y = -2x - 3

3x - 3(-2x - 3) = -9

3x + 6x + 9 = -9

9x + 9 = -9

    - 9    -9

9x = -18

/9     /9

x = -2

y = -2x - 3

y = -2(-2) -3

y = 4 - 3

y = 1

(x, y) --> (-2,1)

Check your answer:

y = -2x - 3

1 = -2(-2) - 3

1 = 4 - 3

1 = 1

This statement is true

Hope this helps!

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The French club is holding a car wash fundraiser. They are going to charge $20 per car , and expect between 30 and 100 cars. Ide
liberstina [14]
Independent variable = number of cars with domain 30 to 100 cars
Dependent variable = money raised with range $600 to $2000
7 0
3 years ago
Read 2 more answers
Identify each expression with a sum of x2 + 3x +1.
Yuki888 [10]

Answer:

There are no like terms.

Step-by-step explanation:

5 0
2 years ago
X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?
cluponka [151]

Answer:

x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}} and y=-1,\frac{1}{2}

The ordered pair solutions are (-\sqrt{\frac{7}{4}},0.5), (\sqrt{\frac{7}{4}},0.5), (-1,-1), and (1,-1).

Step-by-step explanation:

I'm assuming the system is \left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.:

x^2+y^2=2

x^2+(2x^2-3)^2=2

x^2+(4x^4-12x^2+9)=2

x^2+4x^4-12x^2+9=2

4x^4-11x^2+9=2

4x^4-11x^2+7=0

x^4-11x^2+28=0

(x^2-7)(x^2-4)=0

(4x^2-7)(x^2-1)=0

4x^2-7=0

4x^2=7

x^2=\frac{7}{4}

x=\pm\sqrt{\frac{7}{4}}

x^2-1=0

x^2=1

x=\pm1

y=2x^2-3

y=2(\pm\sqrt{\frac{7}{4}})^2-3

y=2({\frac{7}{4}})-3

y=\frac{7}{2}-3

y=\frac{1}{2}

y=2x^2-3

y=2(\pm1)^2-3

y=2(1)-3

y=2-3

y=-1

Therefore, x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}} and y=-1,\frac{1}{2}

The ordered pair solutions are (-\sqrt{\frac{7}{4}},0.5), (\sqrt{\frac{7}{4}},0.5), (-1,-1), and (1,-1).

4 0
2 years ago
Seven years ago, kodi found a box of old baseball cards in the garage. since then, he has added a consistent number of cards to
Katena32 [7]
(3,52)(7,108)
slope = (108 - 52) / (7 - 3) = 56/4 = 14

y = mx + b
slope(m) = 14
(3,52)...x = 3 and y = 52
sub and find b, the y int (the original amount of cards)
52 = 3(14) + b
52 = 42 + b
52 - 42 = b
10 = b

so ur equation is y = 14x + 10....with x being the number of years and y being the total cards. <== ur equation is y = 14x + 10

He started with 10 cards....and has been adding 14 cards every year.

so after 10 years...
y = 14(10) + 10
y = 140 + 10
y = 150 <== after 10 years, he will have 150 cards
8 0
3 years ago
Find the distance and midpoint of a segment with the following endpoints: (5,-1) and (-9,-1)
Likurg_2 [28]

Answer:

d = 14

(-2,-1)

General Formulas and Concepts:

  • Order of Operations: BPEMDAS
  • Distance Formula: d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}
  • Midpoint Formula: (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Step-by-step explanation:

<u>Step 1: Define</u>

(5, -1)

(-9, -1)

<u>Step 2: Find distance </u><em><u>d</u></em>

  1. Substitute:                    d = \sqrt{(-9-5)^2+(-1-(-1))^2}
  2. Simplify:                        d = \sqrt{(-9-5)^2+(-1+1)^2}
  3. Subtract/Add:               d = \sqrt{(-14)^2+(0)^2}
  4. Evaluate:                       d = \sqrt{196}
  5. Evaluate:                       d = \14

<u>Step 3: Find Midpoint</u>

  1. Substitute:                    (\frac{5-9}{2},\frac{-1-1}{2})
  2. Subtract:                       (\frac{-4}{2},\frac{-2}{2})
  3. Divide:                          (-2,-1)
7 0
3 years ago
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