Answer:
<h3>
The width (side perpedicular to the barn):
<u>x = 8 m</u></h3><h3> The lenght (side parallel to the barn):
<u>y = 16 m</u> </h3>
Step-by-step explanation:
x - the width of the barn
She has 32 m of fencing so for the lenght remain (32-2x) m of fencing:
y = 32 - 2x
Area of the fencing: A = x•y
A(x) = x•(32 - 2x)
A(x) = -2x² + 32x ← quadratic function
The maximum value of quadratic function occurs at: 
a = -2, b = 32
32-2x = 32 - 2•8 = 16
If point A is between B and C, then CA+AB = CB by the segment addition postulate. This is the idea of taking two smaller segments to "glue" them together to form a larger segment. Or you can think in reverse: take some larger segment and split it somewhere in between the endpoints (not necessarily the halfway point), this will produce two smaller segments.
For example: you have a ruler that is 12 inches. Take a saw and cut the ruler at the "2 inch" marker. You'll end up with two smaller pieces of plastic: one of which is 2 inches, the other 10 inches. The two smaller pieces can be taped together to reform the original 12 inch ruler.
Answer: True
Step-by-step explanation:
