Answer:
30.22 hours
Explanation:
Given data:
A= l² = (2 x 
)² = 4 x 
m²
Length 'L' = 5m
current '
' = 2 A
density of free electrons 'n'= 8.5 x 
/m³
Current Density 'J' = / A
J= 2/4 x
J= 5 x 
A/m²
We can determine the time required for an electron to travel the length of the wire by
T= L/ Vd
Where,
L is length and Vd is drift velocity.
Vd can be defined by J/ n|q|
where,
n is the charge-carrier number density
|q| is is the charge carried by each charge carrier
=>1.6 x 
C
T= L/ Vd
Therefore,
T= L . n|q| / J
T= (4 x 8.5 x x |1.6 x |)/5 x
T= 108800 seconds =>1813.33 minutes
Converting minute into hours:
T= 30.22 hours
Thus, time that is required for an electron to travel the length of the wire is 30.22 hours
The pressure value is given by the equation,
Where,
represents the density of the liquid
g= gravity
h= Heigth
A) For the measurement of the guage pressure we have the data data,
Replacing we get,
![[tex]P_g = (13.6*10^3)(9.8)(0.0930)](https://tex.z-dn.net/?f=%5Btex%5DP_g%20%3D%20%2813.6%2A10%5E3%29%289.8%29%280.0930%29)
P_g = 12395Pa[/tex]
In order to find the Absolute pressure, we perform a sum between the atmospheric pressure and that of the Gauge,
B) The atmospheric pressure at sea level is 101325Pa, assuming ideal conditions, we will take this pressure for our calculation, so
Answer:
The size of an object is directly proportional to the gravity
Explanation:
The size of an object has significant impact on the gravity exerted by such a body.
The more massive a body is, the larger the gravity it exerts.
The reason for this is because of the newton's law of universal gravitation.
- It states that "the gravitational force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distances between them".
- As such, gravity is directly proportional to mass
Answer ;
Minimum required volume = 0.635m3
Maximum internal pressure = 74.35bar
Explanation:
The detailed step by step calculation using the vanderwaal's equation of state for ideal gases is as shown in the attachment.
