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garri49 [273]
3 years ago
10

Darwin observed fossils of glyptodonts, which are now extinct. Living armadillos are the only animals remaining on Earth that ar

e similar to glyptodonts. Armadillos live in the same places that glyptodonts lived.
What did Darwin most likely conclude about the two types of animals?

Glyptodonts were better adapted to the environment.
Glyptodonts outcompeted armadillos for food.
Glyptodonts were early relatives of armadillos.
Glyptodonts had the exact same adaptations as armadillos.
Physics
2 answers:
stiv31 [10]3 years ago
7 0

Answer:

C Glyptodons were early relatives of armadillos.

Explanation:

Darwin would have come to this conclusion because glyptodons over time became armadillos, which you can tell by evolution that they were better evolved to survive than glyptodons. Due to this, they outlived the glyptodons.

Explanation:

Inessa [10]3 years ago
6 0

Answer:

3. Glyptodons were early relatives of armadillos.

Explanation:

Darwin would have come to this conclusion because glyptodons over time became armadillos, which you can tell by evolution that they were better evolved to survive than glyptodons. Due to this, they outlived the glyptodons.

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Answer:

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3 years ago
A toy car is moving across a table with a velocity of 7.0 m/s and drives off the end. The table is 1.8 m tall. How long will the
KatRina [158]

Answer:

Option D - 0.2 s

Explanation:

We are given;

Initial velocity; u = 7 m/s

Height of table; h = 1.8m

Now,since we want to find the time the car spent in the air, we will simply use one of Newton's equation of motion.

Thus;

h = ut + ½gt²

Plugging in the relevant values, we have;

1.8 = 7t + ½(9.8)t²

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t = -1.65 or 0.22

We can't have negative t value, thus we will pick the positive one.

So, t = 0.22 s

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3 years ago
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2 years ago
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6 0
3 years ago
Uranium-235 decays to thorium-231 with a half-life of 700 million years. When a rock was formed, it contained 6400 million urani
Dahasolnce [82]

Answer:

proof in explanation

Explanation:

First, we will calculate the number of half-lives:

n = \frac{t}{t_{1/2}}

where,

n = no. of half-lives = ?

t = total time passed = 2100 million years

t_{1/2} = half-life = 700 million years

Therefore,

n = \frac{2100\ million\ years}{700\ million\ years}\\\\n = 3

Now, we will calculate the number of uranium nuclei left (n_u):

n_u = \frac{1}{2^{n} }(total\ nuclei)\\\\n_u = \frac{1}{2^{3} }(6400\ million)\\\\n_u = \frac{1}{8}(6400\ million)\\\\n_u =  800\ million

and the rest of the uranium nuclei will become thorium nuclei (u_{th})

n_{th} = total\ nuclei - n_u\\n_{th} = 6400\ million-800\ million\\n_{th} = 5600\ million

dividing both:

\frac{n_{th}}{n_u}=\frac{5600\ million}{800\ million} \\\\n_{th} = 7n_u

<u>Hence, it is proven that after 2100 million years there are seven times more thorium nuclei than uranium nuclei in the rock.</u>

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