Using Newton's Second Law, we can find the air resistance. We know the net force is equal to mass times acceleration.
Darwin observed fossils of glyptodonts, which are now extinct. Living armadillos are the only animals remaining on Earth that ar
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Answer:
16 J
Explanation:
It is given that,
Work done, W = 2 J
A spring is stretched by 2.0 cm from its equilibrium length
We need to find how much more work will be required to stretch it an additional 4.0 cm.
Let k is the spring constant of the spring. When W = 2J, and x = 2 cm, then energy required to stretch the spring is :
The energy required to stretch the spring from 2 cm to additional 4 cm i.e. 2+4= 6 cm.
So, the required work done is 16 J.
Answer:
P = 40.7kPa
Explanation:
To find the pressure on a surface 6 meter below you use the following formula, which takes into account the heights in which pressures are measured and also the density of the fluid and the gravitational acceleration:
(1)
P2: pressure for a height of -6 m = ?
P1: pressure for a height of -2 m = 1.5kPa = 1500 Pa
ρ: density of water = 1000kg/m^3
g: gravitational acceleration = 9.8 ms^2
y2: -6m
y1: -2m
(the height is measure from the water level, because of that, the heights are negative)
You solve the equation (1) for P1:
(2)
Next, you replace the values of all variables in equation (2):
hence, the pressure on a surface 6 m below the water level is 40.7kPa
Given data:
* The mass of the Ceres is,
* The mass of the astronaut is,
* The radius of the Ceres is,
Solution:
The gravitational force acting on the astronaut due to the Ceres is,
where G is the gravitational force constant,
Substituting the known values,
The weight of the astronaut on the Ceres is equal to the gravitational force acting on the astronaut.
Thus, the weight of the astronaut on the Ceres is 17.7 N.