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garri49 [273]
3 years ago
10

Darwin observed fossils of glyptodonts, which are now extinct. Living armadillos are the only animals remaining on Earth that ar

e similar to glyptodonts. Armadillos live in the same places that glyptodonts lived.
What did Darwin most likely conclude about the two types of animals?

Glyptodonts were better adapted to the environment.
Glyptodonts outcompeted armadillos for food.
Glyptodonts were early relatives of armadillos.
Glyptodonts had the exact same adaptations as armadillos.
Physics
2 answers:
stiv31 [10]3 years ago
7 0

Answer:

C Glyptodons were early relatives of armadillos.

Explanation:

Darwin would have come to this conclusion because glyptodons over time became armadillos, which you can tell by evolution that they were better evolved to survive than glyptodons. Due to this, they outlived the glyptodons.

Explanation:

Inessa [10]3 years ago
6 0

Answer:

3. Glyptodons were early relatives of armadillos.

Explanation:

Darwin would have come to this conclusion because glyptodons over time became armadillos, which you can tell by evolution that they were better evolved to survive than glyptodons. Due to this, they outlived the glyptodons.

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_________ liquids and gases exert a buoyant force.
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Hitungkan pecutan bagi blok di bawah: / Cal<br>(a)<br>m= 2 kg<br>F= 8.0 N​
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Answer:

Acceleration = 4 m/s²

Explanation:

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A person jogs eight complete laps around a quarter-mile track in a total time of 12.5 min. Calculate (a) the average speed and (
Margarita [4]

\large\displaystyle\text{$\begin{gathered}\sf \huge \bf{\underline{Data:}} \end{gathered}$}

  • \large\displaystyle\text{$\begin{gathered}\sf 1\ mile = 1609.34 \ m \end{gathered}$}
  • \large\displaystyle\text{$\begin{gathered}\sf  1/4 \ mile = 402.33 \ m \end{gathered}$}

                           \large\displaystyle\text{$\begin{gathered}\sf 12.5 \not{min}*\frac{60 \ s}{1\not{min}}=750 \ s \end{gathered}$}

                   \large\displaystyle\text{$\begin{gathered}\sf \bf{A) \ Calculate \ the \ average \ speed: } \end{gathered}$}

                         \large\displaystyle\text{$\begin{gathered}\sf 402.33 \ m*8 \ laps = 3218.64 \ m \end{gathered}$}

                         \large\displaystyle\text{$\begin{gathered}\sf d=3218.64 \ m \end{gathered}$}

                         \large\displaystyle\text{$\begin{gathered}\sf t=750 \ s \end{gathered}$}

                         \large\displaystyle\text{$\begin{gathered}\sf V=\frac{d}{t} \ \ \ \ \ \  V= \frac{3218.64 \ m }{750 \ s} \end{gathered}$}\\\\\\\large\displaystyle\text{$\begin{gathered}\sf V=4.29 \ m/s \end{gathered}$}

                  \large\displaystyle\text{$\begin{gathered}\sf \bf{B) \ Calculate \ the \ average \ speed \  in \ m/s} \end{gathered}$}

                          \large\displaystyle\text{$\begin{gathered}\sf V=402.33 \ m \end{gathered}$}  

                          \large\displaystyle\text{$\begin{gathered}\sf t=750 \ s \end{gathered}$}

                          \large\displaystyle\text{$\begin{gathered}\sf V=\frac{D}{T} \ \ \ \ \ V=\frac{402.33 \ m}{750 \ s}   \end{gathered}$}\\\\\\\large\displaystyle\text{$\begin{gathered}\sf V= 0.53 \ m/s \end{gathered}$}

4 0
2 years ago
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