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IRISSAK [1]
3 years ago
7

Sammy feels an ocean breeze as he plays volleyball at the beach. Why do ocean winds or sea breezes blow toward shore during the

day? Question 2 options: Air over the beach heats up, rises and is replaced by ocean air. Earth's rotation causes air to blow toward land. he energy of the ocean storms push air toward shore. Ocean air is less dense, so it rises to replace air over the land.
Physics
1 answer:
DedPeter [7]3 years ago
4 0

The heat coming from the sun warms the land more quickly than the sea. As a result of these, the air near the land warm up and rises and the cooler air from the sea moves in to replace the risen air. The correct answer is option A

There will be heat transfer from a region of higher temperature to the region of lower temperature. But in the case of land and sea breeze, the transfer of heat are the result of convectional current in nature. Because the land is a better absorber of heat and also has a lower specific heat capacity compare to sea, during the day, the heat coming from the sun warms the land more quickly than the sea. As a result of these, the air near the land warm up and rises.

The cooler air from the sea moves in to replace the risen air.

Why do ocean winds or sea breezes blow toward shore during the day ? It is because air over the beach heats up, rises and is replaced by ocean air.

Therefore, option A is correct

Learn more here : brainly.com/question/1114842

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A wheel starts from rest and has an angular acceleration that is given by α (t) = (6.0 rad/s4)t2. After it has turned through 10
marissa [1.9K]

Answer:

75 rad/s

Explanation:

The angular acceleration is the time rate of change of angular velocity. It is given by the formula:

α(t) = d/dt[ω(t)]

Hence: ω(t) = ∫a(t) dt

Also, angular velocity is the time rate of change of displacement. It is given by:

ω(t) = d/dt[θ(t)]

θ(t) = ∫w(t) dt

θ(t) = ∫∫α(t) dtdt

Given that: α (t) = (6.0 rad/s4)t² = 6t² rad/s⁴. Hence:

θ(t) = ∫∫α(t) dtdt

θ(t) = ∫∫6t² dtdt =∫[∫6t² dt]dt

θ(t) = ∫[2t³]dt = t⁴/2 rad

θ(t) = t⁴/2 rad

At θ(t) = 10 rev = (10 *  2π) rad = 20π rad, we can find t:

20π = t⁴/2

40π = t⁴

t = ⁴√40π

t = 3.348 s

ω(t) = ∫α(t) dt = ∫6t² dt = 2t³

ω(t) = 2t³

ω(3.348) = 2(3.348)³ = 75 rad/s

7 0
3 years ago
NEED HELP NOW DUE TODAY Which of these statements is most likely correct about Newton's law on gravity? (2 points)
yKpoI14uk [10]
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4 0
3 years ago
A 50 kg person receives an absorbed dose of gamma radiation of 20 millirads. What is the total energy absorbed?.
Masteriza [31]

For a 50 kg person receives an absorbed dose of gamma radiation of 20 millirads,  the total energy absorbed is mathematically given as

E=0.1457J

<h3>What is the total energy absorbed?</h3>

Generally, the equation for the total energy absorbed  is mathematically given as

E=mass*gamma radiation

Therefore

E=50*20*19^{-3}

E=0.1457J

In conclusion,  the total energy absorbed

E=0.1457J

Read more about Energy

brainly.com/question/13439286

4 0
2 years ago
Please help
Hitman42 [59]

Answer:

3200 m/s

Explanation:

The speed of Sound through Argon is 319.

The speed of sound in any chemical element in the fluid phase has one temperature-dependent value. In the solid phase, different types of sound wave may be propagated, each with its own speed: among these types of wave are longitudinal (as in fluids), transversal, and (along a surface or plate) extensional.

If argon could exist as solid, then 3200 m/s is the best speed.

7 0
3 years ago
Read 2 more answers
A national college researcher reported that 67%of students who graduated from high school in 2012 enrolled in college. Twenty-ni
dsp73

Answer:

Explanation:

Theorem of Binomial Distribution will apply here.

n = 29 , p = .67 , q = 0.33

mean = np = 29 x .67 = 19.43

Standard Deviation = √npq

= √29 x .67 x .33

= √6.4

= 2.53

=

4 0
3 years ago
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