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IRISSAK [1]
3 years ago
7

Sammy feels an ocean breeze as he plays volleyball at the beach. Why do ocean winds or sea breezes blow toward shore during the

day? Question 2 options: Air over the beach heats up, rises and is replaced by ocean air. Earth's rotation causes air to blow toward land. he energy of the ocean storms push air toward shore. Ocean air is less dense, so it rises to replace air over the land.
Physics
1 answer:
DedPeter [7]3 years ago
4 0

The heat coming from the sun warms the land more quickly than the sea. As a result of these, the air near the land warm up and rises and the cooler air from the sea moves in to replace the risen air. The correct answer is option A

There will be heat transfer from a region of higher temperature to the region of lower temperature. But in the case of land and sea breeze, the transfer of heat are the result of convectional current in nature. Because the land is a better absorber of heat and also has a lower specific heat capacity compare to sea, during the day, the heat coming from the sun warms the land more quickly than the sea. As a result of these, the air near the land warm up and rises.

The cooler air from the sea moves in to replace the risen air.

Why do ocean winds or sea breezes blow toward shore during the day ? It is because air over the beach heats up, rises and is replaced by ocean air.

Therefore, option A is correct

Learn more here : brainly.com/question/1114842

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What is the "basics" of a proper experiment?
lara31 [8.8K]

Answer:

sorry in my sense, an experiment once only changes one variable and need a control setup for experimental setup to make sure is fair test

5 0
3 years ago
An object on earth weighs 120 N. What is it’s mass ?
inna [77]
Weight = (mass) x (gravity)

120 N = (mass) x (9.8 m/s²)

Mass = (120 N) / (9.8 m/s²)

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7 0
3 years ago
Read 2 more answers
A bullet fired horizontally hits the ground in 0.5 sec. If it had been fired with a much higher speed in the same direction, and
stira [4]

Answer:

3. 0.5 sec.

Explanation:

A bullet fired horizontally follows a projectile motion, which consists of two independent motions:

- A horizontal motion with constant speed

- A vertical motion with  constant acceleration, g = 9.8 m/s^2, towards the ground

The time taken for the bullet to reach the ground can be calculated just by considering the vertical motion:

y(t) = h + v_{0y} t - \frac{1}{2}gt^2

where y is the vertical position at time t, h is the initial height, and v_{0y} is the initial vertical velocity of the bullet.

Since the bullet is fired horizontally, v_{0y}=0. So the equation becomes

y(t) = h - \frac{1}{2}gt^2

And the time that the bullet takes to reach the ground can be found by requiring y=0 and solving for t:

t=\sqrt{\frac{2h}{g}}

As we can see, in this equation there is no dependance on the initial speed of the bullet: therefore, if the bullet is fired still horizontally but with a different speed, it will still take the same time (0.5 s) to reach the ground.

4 0
3 years ago
Sarah throws a ball directly upward at the edge of a cliff with a starting velocity of 3.0 m/s
strojnjashka [21]

Answer:

The correct answer is t = 0.92s

Explanation:

Initial velocity v​0 = 3.0 m/s

Displacement Δy = ?

Acceleration a = -9.8m/s2

Final velocity v = -6.0m/s

Time t=? Target unknown

We can use the kinematic formula missing Δy to solve for the target unknown t:

V=v0+at

We can rearrange the equation to solve to t:

V-v0=at

t= v-v0/a

Substituting the known value into the kinematic formula gives:

t= (-6.0m/s)-(3.0m/s)

————————————

-9.8m/s2

= -9m/s

—————-

-9.8m/s2

=0.92s

6 0
3 years ago
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