Answer:
4.23 L
Explanation:
The question doesn't specify pressure so
i will just assume it is 1 atm. This won't affect the answer. The same result can be achieved using the combined gas law and Charle's law, so long as pressure is kept constant in the combined gas law.
Using the combined gas law
(P1 × V1)/ T1 = (P2 × V2)/T2
where
P1 = 1 atm
V1 = 4 L
T1 =293.15 K
P2 = 1 atm
V2 =?
T2=310.15 K
We can rearrange the equation to make V2 the subject
V2= (((P1 × V1)/ T1) × T2)/P2
V2 = (((1 × 4)/293.15)×310.15)/1
V2 = 4.23 L
Using Charle's law
V1/ T1 = V2/ T2
V2 = (V1/T1) × T2
V2 = (4/293.15) ×310.15
V2 =4.23L
Hopefully this is correct
