Answer:
When you are exercising, your muscles need extra oxygen—some three times as much as resting muscles. This need means that your heart starts pumping faster, which makes for a quicker pulse. Meanwhile, your lungs are also taking in more air, hence the harder breathing.
Explanation:
<h3><u>Answer;</u></h3>
1) 2H2(g)+O2(g)⟶Δ2H2O(g)+483.6kJ - Exothermic
2) 6CO2(g)+6H2O(l)+15000kJ⟶C6H12O6(aq)+6O2(g) - Exothermic
3) 2Al(s)+Fe2O3(s)⟶Al2O3(s)+2Fe(s)+850kJ - Exothermic
<h3><u>Explanation</u>;</h3>
- Exothermic Reaction is a chemical reaction in which heat is given out is known as exothermic reaction, while, and endothermic Reaction is a chemical reaction in which heat energy is absorbed is known as endothermic reaction.
- The reaction between carbon dioxide and water is an example of an exothermic reaction. When most gases dissolve in solution, the process is exothermic meaning that heat is released as the gas dissolves
- The reduction of ferric oxide by aluminium is highly exothermic and therefore the iron formed will be in the molten state.
Answer:
The answer is C. Coil
Explanation:
Water is a renewable resource. So is sunlight. Coil is not. I know because it is a fossil fuel. Coil takes millions of years to form in the earth. Therefore, it is not a renewable resource.
To solve this we assume that the gas inside the balloon is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:
T1 / V1 = T2 / V2
V2 = T2 x V1 / T1
V2 =90 x 20 / 360
<span>V2 = 5 L</span>
Answer:
Concentration of hydroxide-ion at equivalence point = 
Explanation:
1 mol of 
reacts with 1 mol of KOH to produce 1 mol of 
At equivalence point, all gets converted to .
Moles of produced at equivalence point is equal to moles of KOH added to reach equivalence point.
So, moles of produced = 
Total volume of solution at equivalence point = (25.00+43.76) mL = 68.76 mL
Concentration of at equivalence point = 
produced at equivalence point is due to hydrolysis of . We have to construct an ICE table to calculate concentration of at equivalence point.
I:0.0897 0 0
C: -x +x +x
E: 0.0897-x x x
![\frac{[HC_{3}H_{5}O_{2}][OH^{-}]}{[C_{3}H_{5}O_{2}^{-}]}=K_{b}(C_{3}H_{5}O_{2}^{-})=\frac{10^{-14}}{K_{a}(HC_{3}H_{5}O_{2})}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BHC_%7B3%7DH_%7B5%7DO_%7B2%7D%5D%5BOH%5E%7B-%7D%5D%7D%7B%5BC_%7B3%7DH_%7B5%7DO_%7B2%7D%5E%7B-%7D%5D%7D%3DK_%7Bb%7D%28C_%7B3%7DH_%7B5%7DO_%7B2%7D%5E%7B-%7D%29%3D%5Cfrac%7B10%5E%7B-14%7D%7D%7BK_%7Ba%7D%28HC_%7B3%7DH_%7B5%7DO_%7B2%7D%29%7D)
species inside third bracket represent equilibrium concentrations
So, 
or, 
So, 
M =
So, concentration of hydroxide-ion at equivalence point = x M =
